A cat jumps from a balcony. About how fast is the cat moving after 1.5 s?
1 answer:
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Answer:
The horizontal component of the velocity is 21.9 m/s.
Explanation:
Please see the attached figure for a better understanding of the problem.
Notice that the vector v and its x and y-components (vx and vy) form a right triangle. Then, we can use trigonometry to find the magnitude of vx, the horizontal component of the velocity.
To find vx, let´s use the following trigonometric rule of right triangles:
cos α = adjacent / hypotenuse
cos 5.7° = vx / 22 m/s
22 m/s · cos 5.7° = vx
vx = 21.9 m/s
The horizontal component of the velocity is 21.9 m/s.
Answer:
a = 1.5*10^-3 m/s^2
x = 0.033m = 3.3cm
Explanation:
To calculate the acceleration and the distance traveled by the car you use the following formulas:
(1)
(2)
v: final velocity = 0,255 km/h
vo: initial velocity = 0 m/s
t: time = 3/4 min
a: acceleration = ?
x: distance
In order to use the equations (1) and (2) you first convert the units of the final velocity to m/s, and the time to seconds.
Next, you solve the equation (1) for the acceleration a:
With this value of a you can calculate the distance traveled by the car, by using the equation (2):
hence, the acceleration of the car is 1.5*10^-3 m/s^2 and the distance traveled in 3/4 min is 0.033m