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Aneli [31]
4 years ago
11

A truck driving along a highway road has a large quantity of momentum. If it moves at the same speed but has twice as much mass,

its momentum is ________________.
Physics
1 answer:
oee [108]4 years ago
3 0

If the truck moves at same speed but twice as much mass, its momentum is increased twice.

Answer:

Explanation:

Momentum is defined as the force experienced by any object for a given time. In other words, it is the measure of the mass and velocity required for a certain motion. So it is determined as the product of mass and velocity of any object.

Momentum = Mass × Velocity.

As momentum is directly proportional to both mass and velocity, increase in any one of these two quantities keeping the other constant will lead to increase in the momentum.

So in the present case, it is stated as speed is kept constant and the mass is increased twice, then the momentum will also increase twice.

New momentum = 2 ×mass × velocity = 2 × old momentum

If the truck moves at same speed but twice as much mass, its momentum is increased twice.

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A zebra starts from rest and accelerates at 1.9 m/s2 what will be the acceleration after 5 seconds
Alex73 [517]

Answer:

d = 23.75 m

The zebra has gone 23.75m after 5 seconds.

Corrected question;

A zebra starts from rest and accelerates at 1.9 m/s2. How far has the zebra gone after 5 seconds.

Explanation:

From the equation of motion;

d = vt + 0.5at^2 .........1

Where;

d = displacement

v = initial velocity = 0

t = time taken= 5 seconds

a = acceleration = 1.9 m/s^2

Substituting the given values into equation 1;

d = 0(5) + 0.5(1.9×5^2)

d = 0.5(1.9×5^2)

d = 23.75 m

The zebra has gone 23.75m after 5 seconds.

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4 years ago
Using an example, explain how small atoms are.
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4 0
3 years ago
What type of evidence is the best indicator of how closely two species are related
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5 0
3 years ago
Read 2 more answers
A spring whose stiffness is 980 N/m has a relaxed length of 0. 50 m. If the length of the spring changes from 0. 25 m to 0. 81 m
Gelneren [198K]

151.9j

Explanation:

PE=1/2kx^2

PE=1/2(980)(.50)= 245j

PE=(1/2)(980)(.81)= 396.9j

396.9- 245= 151.9j

8 0
2 years ago
A boy of mass 30.0 kg is sledding down a 70.0-m slope starting from rest. The slope is angled at 15.0° below the horizontal. Aft
Studentka2010 [4]

The speed of the boy and his friend at the bottom of the slope is 16.52 m/s.

<h3>Their speed at the bottom</h3>

Apply the principle of conservation of energy,

E(up) - E(friction) = E(bottom)

mg sin(15) + ¹/₂(M + m)u² - μ(M + m)cos 15 = ¹/₂(M + m)v²

v = \sqrt{2[\frac{mgd \ sin15 \ + \frac{1}{2}(M + m)u^2 \ -\mu (M + m)g cos\ 15 }{M + m}] }

where;

  • u is the speed of the after 28 m

u = √2gh

u = √(2gL sin15)

u = √(2 x 9.8 x 28 x sin 15)

u = 11.92 m/s

v = \sqrt{2[\frac{(30)(9.8)(70) \ sin15 \ + \frac{1}{2}(30 + 50)(11.92)^2 \ - 0.12 (30 + 50)9.8 cos\ 15 }{30 + 50}] }\\\\v = 16.52 \ m/s

Thus, the speed of the boy and his friend at the bottom of the slope is 16.52 m/s.

Learn more about speed here: brainly.com/question/6504879

#SPJ1

8 0
2 years ago
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