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emmainna [20.7K]
3 years ago
7

Floating in deep space, you find yourself at rest next to a small asteroid. You reach out and tap the asteroid with a hammer. Wh

at happens to you in this process?
Physics
1 answer:
Andrei [34K]3 years ago
4 0

Answer:

There is a force that has the same magnitude as that of the hammer applied on the astronaut and with direction away from the asteroid, movement is given by

                F_hammer - F_Gravitation = m a

Explanation:

For this exercise we will propose its solution from Newton's third law, which states that every action has a reaction of equal magnitude, but felt different.

As it is in space, we must assume that it is not subject to the gravitational attraction of nearby bodies, except the asteroid that attracts it. When he extends his hand and hits the asteroid, he exerts a force on him, by Newton's third law he responds with a force of equal magnitude applied to the astronaut, therefore without the two they are not united they could separate if this force is greater than the force of universal attraction between the two.

In summary There is a force that has the same magnitude as that of the hammer applied on the astronaut and with direction away from the asteroid, movement is given by

                F_hammer - F_Gravitation = m a

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You look in the sky and see two jetliners that you know are of equal size, yet one appears to be much larger. Because of your kn
Ksju [112]

Answer:

Because of the knowledge of <u>relative size</u>, it will be assumed that the smaller jetliner is farther away.

Explanation:

According to the theory of relative size, the distance that an object has to the viewing individual affects the perception of the individual regarding the size of the object.

As stated in this case, one of the jetliners is farther away from the other. Therefore, even if the jets are of equal size, the one that is at a greater distance is perceived to be smaller as it is at a greater viewing range. The one that is nearer to the individual seems bigger in comparison to the one farther away due to a closer viewing range.

Therefore, the jet that is nearer appears larger.

To know more about relative size, refer to:

brainly.com/question/19998265

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8 0
2 years ago
0.054x2.33x90............
guapka [62]
<h2>0.054×2.33×90</h2><h3>=0.11582×90</h3><h3>=11.3238</h3>

please mark this answer as brainlist

5 0
3 years ago
Which term best describes the change in frequency of waves when there is motion between the source of the waves and the observer
ahrayia [7]
The Doppler effect is the term that best describes the change in frequency of waves when there is motion between the source of the waves and the observer. The correct option among all the options that are given in the question is the first option or option "a". I hope the answer helps you.
4 0
3 years ago
Read 2 more answers
A playground ride requires 21 seconds to make one complete revolution
luda_lava [24]

The angular speed of the playground ride is determined as 0.3 rad/s.

<h3>What is angular speed?</h3>

Angular speed is the rate at which an object changes it angles which we measure in radians in a given time.

<h3>Angular speed of the ride</h3>

The angular speed of the ride if the ride makes one complete revolution is calculated as follows;

ω = θ/t

ω = 2π/t

where;

  • ω is angular speed of the ride
  • t is time of motion of the ride

one complete revolution = 2π radians

ω = 2π/21

ω = 0.3 rad/s

Thus, the angular speed of the playground ride is determined as 0.3 rad/s.

Learn more about angular speed here: brainly.com/question/24158647

#SPJ1

The complete question is below;

A playground ride requires 21 seconds to make one complete revolution, what is angular speed of the ride in radian per second.

3 0
2 years ago
A tank with a volume of 0.150 m3 contains 27.0oC helium gas at a pressure of 100 atm. How many balloons can be blown up if each
jekas [21]

Answer:

884 balloons

Explanation:

Assume ideal gas, since temperature is constant, then the product of pressure and volume is constant.

So if pressures reduces from 100 to 1.2, the new volume would be

V_2 = \frac{P_1V_1}{P_2} = \frac{100*0.15}{1.2} = 12.5 m^2

The spherical volume of each of the balloon of 30cm diameter (15 cm or 0.15 m in radius) is

V_b = \frac{4}{3}\pir^3 = \frac{4}{3}\pi 0.15^3 = 0.014 m^3

The number of balloons that 12.5 m3 can fill in is

V_2/V_b = 12.5 / 0.014 = 884

8 0
3 years ago
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