number because a normal karyotype has 22 autosomes and 1 pair of s€x chromosomes
(sorry if I'm wrong)
Answer:
The mentioned parental types are c+m- and c-m+. Thus, the recombinants will be c+m+ and c-m-.
Now, the given distance between c and m is 8 map units. Thus, the recombinant frequency is 8% or 0.08.
The total recombinants from 1000 plaques will come out to be 80,
Thus, the recombinants of each type will be 40.
Total parental type will be 920, and therefore, each parental type count will be 460.
Thus, expected c+m- = 460, expected c-m+ = 460, expected c+m+ = 40 and expected c-m- = 40.
Hey there!
We need to find a common denominator.
5*3= 15
4/5= 12/15
2/3= 10/15
12+10=22
22/15
or
1 7/15
I hope this helps!
~kaikers
Answer:
Anything that has mass and occupies space.
Explanation:
When an individual muscle fiber receives a threshold stimulus, it contracts as much as possible. ... a threshold stimulus is the minimum amount of energy needed to make a muscle fiber contract.
