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Vika [28.1K]
3 years ago
12

A questionnaire is being designed to determine whether most people are or are not in favor of keeping U.S. troops in Iraq. Give

two examples of poorly worded questions, one biased toward each response. You can fabricate or make-up extraneous information for the purpose of this quiz question (no need to use real, factual data).
Mathematics
1 answer:
uranmaximum [27]3 years ago
3 0

Here are the two examples of poorly worded questions that are biased toward each response:

<span>1.       </span>It’s certain that keeping U.S. troops in Iraq is a good decision; we should send more troops there, right?

<span>2.       </span><span>Since keeping U.S. troops should not be kept in Iraq when do you think is the best time to evacuate them?</span>

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The average number of customers per day increased 25 percent during the sale. If the average number of customers per day before
Rasek [7]

Answer:

The average number of customers per day during the sale was 150.

Step-by-step explanation:

This question can be solved using a rule of three.

Before the sale, the average number of customers per day was 120, which is 100% = 1.

Now, there are x customers, and since it is an increase of 25%, it is 100+25 = 125% = 1.25. So

120 - 1

x - 1.25

x = 1.25*120 = 150

The average number of customers per day during the sale was 150.

6 0
3 years ago
For the graphed function f(x) = -(5)* - 3 + 2, calculate the average rate of change from x = 3 to x = 4.
Ilia_Sergeevich [38]

Answer:

-4

Step-by-step explanation:

The average rate of change from x=a to x=b of f(x) is \frac{f(b)-f(a)}{b-a}

The given function is f(x)=-5^{x-3}+2.

f(4)=-5^{4-3}+2=-3.

f(4)=-5^{3-3}+2=1.

The average rate of change from x=3 to x=4 is given by:

\frac{f(4)-f(3)}{4-3}

\frac{-3-1}{4-3}=-4

7 0
3 years ago
Select all the correct answers.
vlabodo [156]
Car load and insurance premium
7 0
3 years ago
Read 2 more answers
What is the difference, in hours and minutes, between these times?
elena-s [515]

Answer:

jhj

Step-by-step explanation:

4 0
3 years ago
The radius of the base of a cylinder is increasing at a rate of 7 millimeters per hour. The height of the cylinder is fixed at 1
Ilya [14]

Answer:

The rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

Step-by-step explanation:

Given:

Rate of increase of base of radius of base of cylinder = 7 mm/hr

Height of cylinder = 1.5 mm

Radius at a certain instant = 12 mm

To find rate of change of volume of cylinder at that instant.

Solution:

Let r represent radius of base of cylinder at any instant.

Rate of increase of base of radius of base of cylinder can be given as:

\frac{dr}{dt}=7\ mm/hr

Volume of cylinder is given by:

V=\pi\ r^2h

Finding derivative of the Volume with respect to time.

\frac{dV}{dt}=\pi\ h\ 2r\frac{dr}{dt}

Plugging in the values given:

\frac{dV}{dt}=\pi\ (1.5)\ 2(12)(7)

\frac{dV}{dt}=252\pi

Using \pi=3.14

\frac{dV}{dt}=252(3.14)

\frac{dV}{dt}=791.28\ mm^3/hr (Answer)

Thus rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

6 0
3 years ago
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