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charle [14.2K]
3 years ago
5

Prompt the user to enter five numbers, being five people's weights. Store the numbers in an array of doubles. Output the array's

numbers on one line, each number followed by one space.
Computers and Technology
1 answer:
Tpy6a [65]3 years ago
4 0
Fddjdidueueyyehdbxhdhdhd
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What are some things that games were historically used for?
madreJ [45]

Answer:

D) All of the above

Explanation:

All of these options are true.

Hope it helps and is correct!

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The following program draws squares recursively. Fill in the missing code. import javax.swing\.\*; import java.awt\.\*; public c
ExtremeBDS [4]

Answer:

The missing code to this question is g.

Explanation:

In this question firstly import packages. Then declaration of the class Test that inherits the JApplet. In this class, we declare the default constructor. In this constructor, we call the add function. Then we declare another class that is SquarePanel. This class inherits JPanel. In this class, we define a method that is paintComponent(). In this method, we define an integer variable. In this method, we perform calculations and pass it to another function that is displaySquares(). In this function, we pass the value as the arguments. So in question the missing code or argument is g.

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3 years ago
Consider the following Stack operations:
maxonik [38]

Answer:

Sequence of popped values: h,s,f.

State of stack (from top to bottom): m, d

Explanation:

Assuming that stack is  initially empty. Suppose that p contains the popped values. The state of the stack is where the top and bottom are pointing to in the stack. The top of the stack is that end of the stack where the new value is entered and existing values is removed. The sequence works as following:

push(d) -> enters d to the Stack

Stack:  

d ->top

push(h) -> enters h to the Stack

Stack:

h ->top

d ->bottom

pop() -> removes h from the Stack:

Stack:

d ->top

p: Suppose p contains popped values so first popped value entered to p is h

p = h

push(f) -> enters f to the Stack

Stack:

f ->top

d ->bottom

push(s) -> enters s to the Stack

Stack:

s ->top

f

d ->bottom

pop() -> removes s from the Stack:

Stack:

f ->top

d -> bottom

p = h, s

pop() -> removes f from the Stack:

Stack:

d ->top

p = h, s, f

push(m) -> enters m to the Stack:

Stack:

m ->top

d ->bottom

So looking at p the sequence of popped values is:

h, s, f

the final state of the stack:

m, d

end that is the top of the stack:

m

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Do warnings ever expire?
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What’s a warning? how do i get one haha
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