You should first .<span>consider how you could shorten the column labels.
Shortening the column labels could be easily done by dragging the column to the size that we want. But when shortening the column labels, some problems might occur such as the content might be distorted and in will become unevenly placed.</span>
Answer:
A motherboard is the main printed circuit board in general-purpose computers and other expandable systems. It holds and allows communication between many of the crucial electronic components of a system
Explanation:
The question above has multiple choices as below;
<span>a. </span>Wear aggregation.
<span>b.
</span>Wear mitigation.
<span>c. </span>Wear prevention
<span>d.
</span>Wear leveling
The answer is d) Wear leveling.
This technique by some SSD controllers to increase the
memory’s lifetime is called wear leveling. The mechanism for this principle is
simple: distribute the entries for all the blocks evenly so that they will wear
out evenly. Flash controller typically manages wear leveling and uses a wear
leveling algorithm to control which physical block to use.
Answer:
C
Explanation:
Putting all government forms on the city web site is the least activity likely to be effective in the purpose of reducing digital divide.
Holding basic computer classes at the community centers will very much help to reduce the digital divide.
Providing free wireless internet connections at locations in low-income neighborhood will also reduce the gap of digital divide
Requiring that every city school has computers that meet a minimum hardware and software will made computing resources available to users thereby reducing digital divide.
Answer:
import java.util.Scanner;
public class ss11{
public static void main (String[]args) {
Scanner keyboard = new Scanner (System.in)
String a1, a2, a3, a4, a5;
int i1, i2, i3, i4, i5;
System.out.println("Enter a four bit binary number:");
a1= keyboard.next();
a2= a1.substring(0,1);
a3= a1.substring(1,2);
a4= a1.substring(2,3);
a5= a1.substring(3,4);
i1 = Integer.parseInt(a2);
i2 = Integer.parseInt(a3);
i3 = Integer.parseInt(a4);
i4 = Integer.parseInt(a5);
i1= i1 * 8;
i2= i1 * 4;
i3= i1 * 2;
i4= i1 * 1;
i5= i1+i2+i3+i4;
System.out.println("The converted decimal number is: +i5);
}
}
Explanation: