Just plug in a = 5, y = -3 in that!
2a + ay = 2(5) + 5(-3) = 10 -15 = -5
thats it!
Answer:
meat = $2.40
vegetables = $ 2.40
fruit = $2.40 + X
= 2.40 ÷ 2
= 1.2
therefore 2.40 + 1.2
=$3.6 (For fruits )
= $3.6 + $2.40 + $2.40
= $ 8.4
Hope this helps .Plzz mark me brainliest
<span>I will assume the more likely selection of $10 per sandal as opposed to $0.05 per sandal.
So with the formulas
c = 1000 + 5x
r = 75x - 0.4x^2
Sandals Cost Revenue Profit or Loss
0 $1,000.00 $0.00 -$1,000.00
1 $1,005.00 $74.60 -$930.40
2 $1,010.00 $148.40 -$861.60
3 $1,015.00 $221.40 -$793.60
4 $1,020.00 $293.60 -$726.40
5 $1,025.00 $365.00 -$660.00
6 $1,030.00 $435.60 -$594.40
7 $1,035.00 $505.40 -$529.60
8 $1,040.00 $574.40 -$465.60
9 $1,045.00 $642.60 -$402.40
10 $1,050.00 $710.00 -$340.00
11 $1,055.00 $776.60 -$278.40
12 $1,060.00 $842.40 -$217.60
13 $1,065.00 $907.40 -$157.60
14 $1,070.00 $971.60 -$98.40
15 $1,075.00 $1,035.00 -$40.00
16 $1,080.00 $1,097.60 $17.60
17 $1,085.00 $1,159.40 $74.40
18 $1,090.00 $1,220.40 $130.40
19 $1,095.00 $1,280.60 $185.60
20 $1,100.00 $1,340.00 $240.00
As you can see 16 sandals and up is profitable.
At what production levels will the company lose money?
a. between 0 and 10 or between 150 and 190 pairs, inclusive
150 and 190
c. between 10 and 20 or between 50 and 100, inclusive
If you add up the profit between 10 and 20 you will get $-484 so 50 and 100
b. between 0 and 15 or between 160 and 200 pairs, inclusive
160 and 200
d. between 15 and 35 or between 75 and 125, inclusive
Neither 15 and 35 or 75 and 125 will lose money.</span>
<h3><em>Answer:</em></h3><h3><em></em></h3><h3><em>number of seats in theater = 1035</em></h3><h3><em></em></h3><h3><em>Step-by-step explanation:</em></h3><h3><em></em></h3><h3><em>Given in question as</em></h3><h3><em></em></h3><h3><em>Total number of rows of seat = 30</em></h3><h3><em></em></h3><h3><em>first row contain seat = 20</em></h3><h3><em></em></h3><h3><em>second row contain seat = 21 .. and so on</em></h3><h3><em></em></h3><h3><em>This is in arithmetic progression as 20 , 21 , 22 , 23 ...... so on</em></h3><h3><em></em></h3><h3><em>Then as number of terms N = 30 and first terms = a = 20</em></h3><h3><em></em></h3><h3><em>so we have to find Tn th terms</em></h3><h3><em></em></h3><h3><em>So, Tn th terms = first term + ( N -1 ) × d d= common difference i.e 1</em></h3><h3><em></em></h3><h3><em> Tn th terms = 20 + (30 - 1) × 1</em></h3><h3><em></em></h3><h3><em>Thus, Tn th terms = 49</em></h3><h3><em></em></h3><h3><em>i.e The number of seats in 30th row = 49</em></h3><h3><em></em></h3><h3><em>Now again Total number of seats in theater</em></h3><h3><em></em></h3><h3><em>sum of Nth terms = </em></h3><h3><em></em></h3><h3><em>so = </em></h3><h3><em></em></h3><h3><em> = 15 × 69 = 1035</em></h3><h3><em></em></h3><h3><em>Hence, Total number of seats in theater = 1035 Answer</em></h3>
