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olchik [2.2K]
3 years ago
15

Which function has the same domain as y = 2 StartRoot x EndRoot

Mathematics
1 answer:
snow_lady [41]3 years ago
4 0
The answer is A. Y=square root of 2x
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Did I do these two correctly?
insens350 [35]
Yes you did those two correctly

6 0
3 years ago
The following equation describes a circle.
Simora [160]

Answer:

Center = (5, -2)  and radius = √33

Step-by-step explanation:

The equation of a circle is given by the formula;

(x-a)² + (y-b)² = r² ; where (a,b) is the center of the circle and r is the radius of the circle.

In this case;

2x² - 20x + 2y² + 8y =40 ;

Dividing both sides of the equation by 2 we get;

x² - 10x + y² + 4y = 20

we can then use the completing the square on both x and y terms.

x² - 10x + y² + 4y = 20

x² + 2(-5)x + 25 + y² + 2(2) y + 4 = 20 +9 + 4

In standard form we get;

(x-5)² + (y+2)² = 33

Therefore;

Center = (5, -2)  and radius = √33

3 0
3 years ago
Simplify (9k6 + 8k4 - 6k2)(4k2 - 5)​
Tasya [4]

Answer:

36k^8-13k^6-64k^4+30k^2

Step-by-step explanation:

36k^8-13k^6-64k^4+30k^2\\9k^6*(4k^2-5)+8k^4*(4k^2-5)-6k^2*(4x^2-5)\\36k^8-45k^6+8k^4*(4k^2-5)-6k^2*(4x^2-5)\\36k^8-45k^6+32k^6-40k^4-6k^2*(4x^2-5)\\36k^8-45k^6+32k^6-40k^4-24k^4+30k^2\\36k^8-13k^6-40k^4-24k^4+30k^2\\36k^8-13k^6-64k^4+30k^2

8 0
3 years ago
Help please?<br> Also explain as much as you can
Natalija [7]
X^3 = 16
x^3 = 4^2

x = ∛4^2
x = 4^2/3

answer
B. 4^2/3

------------------
x^5 = 16
x^5 = 2^4
x = 2^4/5

answer
D. x = 2^4/5

5 0
3 years ago
I WILL GIVE BRAINLIEST PLEASE HELP Solve the equation using inverse operations. Check your solutions. In your final answer, incl
Oksi-84 [34.3K]

Answer:

x=16/3=5.33.

Step-by-step explanation:

Isolate x on one side of the equation.

2+x3=18

2+x*3=18

2+x*3-2=18-2 (First, subtract 2 from both sides.)

18-2 (Solve.)

18-2=16

x*3=16

x*3/3=16/3 (Then, divide by 3 from both sides.)

16/3=5.33

x=16/3=5.33

In conclusion, the final answer is x=16/3=5.33.

4 0
3 years ago
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