What is the value of x in the equation below?

Mathematics

2 answers:

vampirchik [111]3 years ago

5 0

Answer:

x= 7

Step-by-step explanation:

-3-(-8)-(-2)= x

-3+8+2=x (negative multiply negative) = +

-3+10=x

x=7

Viefleur [7K]3 years ago

4 0

Answer:

-9 may be the right answer

You might be interested in

Equation: w = 112 + 8t Which input results in an output of 176? What is the output in the ordered pair (4, 144)?

Grace [21]

9514 1404 393

Answer:

Step-by-step explanation:

Generally, the single variable on the left side of the equation is the "output" or dependent variable, while any other variables on the right side of the equation are considered to be independent variables, or "input."

So, we assume your first question is asking for the value of t that makes w=176. Put the values in the equation and solve for the unknown.

w = 112 +8t

176 = 112 + 8t

64 = 8t . . . . . . . subtract 112

8 = t . . . . . . . . . divide by 8

The input for an output of 176 is 8.

Ordered pairs are always written as ...

(input, output)

So, (4, 144) means the output is 144 for an input of 4.

7 0

3 years ago

Read 2 more answers

Which expression represents the distance between point (0, a) and point (a, 0) on a coordinate grid?

o-na [289]

Answer:

$\sqrt{2} a$

Step-by-step explanation:

The distance between point (x1,y1) and (x2,y2) on a coordinate plane is given by expression $\sqrt{(x1-x2)^2+(y1-y2)^2}$

In the problem given coordinate points are

(0, a) and (a, 0).

Thus, distance between these points are given by

$distance = \sqrt{(x1-x2)^2+(y1-y2)^2}\\=>distance = \sqrt{(0-a)^2+(a-0)^2}\\=>distance = \sqrt{(a)^2+(a)^2}\\\\=>distance = \sqrt{2a^2}\\=>distance = \sqrt{2} a$