If 3mile=28 min
x mile=42 min
cross multiply
x=3/28
therefore if 3/28=1 min
then x mile= 42 min
cross multiply
42 x 3/28 =21 x 3/14
=3 x 3/1
=9
The answer is 9 miles
Answer:
![x \geq 3(y + z)](https://tex.z-dn.net/?f=x%20%5Cgeq%203%28y%20%2B%20z%29)
Step-by-step explanation:
I am going to say that:
Mary's amount is x.
Ashley's amount is y.
Oscar's amount is z.
Mary has at least 3 times the amount of cash that ashley and oscar have combined
Ashley's and Oscar's combined amount is y + z.
3 times this amount is 3(y + z).
At least 3 times means that z is equal or greater than 3(y + z).
So
![x \geq 3(y + z)](https://tex.z-dn.net/?f=x%20%5Cgeq%203%28y%20%2B%20z%29)
Answer: h=7
Step-by-step explanation:
By definition the function in vertex form is:
![f(x)=a(x-h)^{2}+k](https://tex.z-dn.net/?f=f%28x%29%3Da%28x-h%29%5E%7B2%7D%2Bk)
Where (h,k) is the vertex of the parabola.
You must group the terms that contain the same variable in the function:
![f(x)=(x^{2}-14x)+29](https://tex.z-dn.net/?f=f%28x%29%3D%28x%5E%7B2%7D-14x%29%2B29)
Complete the square as following:
![f(x)=(x^{2}-14x+49)+29-49](https://tex.z-dn.net/?f=f%28x%29%3D%28x%5E%7B2%7D-14x%2B49%29%2B29-49)
Now you must rewrite it as following:
![f(x)=(x-7)^{2}-20](https://tex.z-dn.net/?f=f%28x%29%3D%28x-7%29%5E%7B2%7D-20)
Then:
h=7
Answer:
Step-by-step explanation:
f (x) = (5(-4)) + a) (3/5 + 4) ( 6 + b)
f (x) = (-20 + a) (6 2/5) (6 + b)
f ( -20 ) = -20 + -20 (a) (6 2/5) (6 + b)
f ( -20 - 6 2/5 ) = (a) (6 2/5 -6 2/5) (6 + b)
f (-26 2/5 - 6 ) = (a) (6-6 +b)
f (-32 2/5-6) = (a) (b)
Answer:
8 blue chips and 12 red
Step-by-step explanation: