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sammy [17]
4 years ago
7

The table shows the temperatures at noon and 8:00 pm for two locations.

Mathematics
1 answer:
Karolina [17]4 years ago
7 0

Answer:

A the changes were in different directions but the same magnitudes

You might be interested in
At a restaurant a meal used to cost $9, but a new owner decided to raise the price by 13
kari74 [83]

Answer:

$10.17

Step-by-step explanation:

9 x .13 = 1.17

9 + 1.17 = 10.17

6 0
1 year ago
Please help me answer for 35 and 36
dexar [7]

Answer:

35. f(2)=16

36. f(2)=77

Step-by-step explanation:

Question 35:

Given:

f(1)=32

f(n)=f(n-1)\times \frac{1}{2}

Plug in 2 for n and simplify. This gives,

f(2)=f(2-1)\times \frac{1}{2}\\f(2)=f(1)\times \frac{1}{2}\\f(2)=32\times \frac{1}{2}\\f(2)=16

Therefore, term 2 is 16.

Question 36:

Given:

f(1)=11

f(n)=f(n-1)\times 7

Plug in 2 for n and simplify. This gives,

f(2)=f(2-1)\times 7\\f(2)=f(1)\times 7\\f(2)=11\times 7\\f(2)=77

Therefore, term 2 is 77.

8 0
3 years ago
A survey of 500 high school students was taken to determine their favorite chocolate candy. Of the 500 students surveyed, 150 li
Anika [276]

Answer:

N(AUC∩B') = 121

The number of students that like Reese's Peanut Butter Cups or Snickers, but not Twix is 121

Step-by-step explanation:

Let A represent snickers, B represent Twix and C represent Reese's Peanut Butter Cups.

Given;

N(A) = 150

N(B) = 204

N(C) = 206

N(A∩B) = 75

N(A∩C) = 100

N(B∩C) = 98

N(A∩B∩C) = 38

N(Total) = 500

How many students like Reese's Peanut Butter Cups or Snickers, but not Twix;

N(AUC∩B')

This can be derived by first finding;

N(AUC) = N(A) + N(C) - N(A∩C)

N(AUC) = 150+206-100 = 256

Also,

N(A∩B U B∩C) = N(A∩B) + N(B∩C) - N(A∩B∩C) = 75 + 98 - 38 = 135

N(AUC∩B') = N(AUC) - N(A∩B U B∩C) = 256-135 = 121

N(AUC∩B') = 121

The number of students that like Reese's Peanut Butter Cups or Snickers, but not Twix is 121

See attached venn diagram for clarity.

The number of students that like Reese's Peanut Butter Cups or Snickers, but not Twix is the shaded part

6 0
3 years ago
1.Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. 90 mg wereused in a procedure. Write an equation t
Sophie [7]

1)\text{   }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}

2) 5.625 mg will be left

Explanation:

1) Half-life = 17.5 days

initial amount of Arsenic-74 = 90 mg

To get the equation, we will use the equation of half-life:

\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}

2) we need to find the remaining amount of Arsenic-74 after 70 days

t = 70

\begin{gathered} N_t=\text{ 90\lparen}\frac{1}{2})^{\frac{70}{17.5}} \\ N_t\text{ = 5.625 mg} \end{gathered}

So after 70 days, 5.625 mg will be left

4 0
1 year ago
Can someone please help me find the area?
rewona [7]

Answer:

90+20=110 square cm

Step-by-step explanation

(10*(14-5)+(5*(10-6)

=90+20

=110

4 0
3 years ago
Read 2 more answers
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