Answer and Explanation:
Using javascript:
function dayof_theweek(){
var TodayDate = window. prompt("enter today's date in the format 'year, month, day' ");
var Datenow=new date(TodayDate);
var Dayofweek=Datenow.getday();
var Days=["monday","Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"];
if(Dayofweek==indexOf(Days[Dayofweek]))
{
document.createTextnode(Days[Dayofweek]);
}
}
The program above uses a date object which uses the method getday to get the day of the week(get day returns an integer from 0 to 6).we then use a comparison operator == to test the condition that returned value Dayoftheweek is same with the index of the array Days and then print to a html document. The program may need improvements such as the fact that errors may arise when proper input isn't given, and therefore must be handled.
Answer:
The codes below implement the problem statements
Explanation:
public class Percentages {
public static void computePercent (int a,int b)
{
System.out.println(a+" is "+(a*100/b)+"% of "+b);
}
public static void main(String []args)
{
int a=2;
int b=5;
computePercent(a,b);
computePercent(b,a);
}
}
<u>
</u>
<u>Part(b)
</u>
import java.util.*;
public class Percentages {
public static void computePercent (int a,int b)
{
System.out.println(a+" is "+(a*100/b)+"% of "+b);
}
public static void main(String []args)
{
Scanner s= new Scanner(System.in);
int a=s.nextInt();
int b=s.nextInt();
computePercent(a,b);
computePercent(b,a);
}
}
<span>A linear bus topology uses a common background cable to connect all network devices.</span>
