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fiasKO [112]
3 years ago
11

A specialty shop procures silver necklaces for 15$ a piece and offers them to customers for 33$ each. What is the mark-up percen

tage?
Mathematics
1 answer:
lidiya [134]3 years ago
6 0

Answer:

54.5%

Step-by-step explanation:

Given data

Cost price= $15

Selling price= $33

Mark up percent =????

%markup= selling-cost/selling*100

substitute

%markup= 33-15/33*100

%markup= 18/33*100

%markup=0.545*100

%markup= 54.5%

Hence the Percent markup is 54.5%

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Drupady [299]

Answer:

a'(d) = \frac{d}{5} + \frac{3}{5}

a(a'(d)) = a'(a(d)) = d

Step-by-step explanation:

Given

a(d) = 5d - 3

Solving (a): Write as inverse function

a(d) = 5d - 3

Represent a(d) as y

y = 5d - 3

Swap positions of d and y

d = 5y - 3

Make y the subject

5y = d + 3

y = \frac{d}{5} + \frac{3}{5}

Replace y with a'(d)

a'(d) = \frac{d}{5} + \frac{3}{5}

Prove that a(d) and a'(d) are inverse functions

a'(d) = \frac{d}{5} + \frac{3}{5} and a(d) = 5d - 3

To do this, we prove that:

a(a'(d)) = a'(a(d)) = d

Solving for a(a'(d))

a(a'(d))  = a(\frac{d}{5} + \frac{3}{5})

Substitute \frac{d}{5} + \frac{3}{5} for d in  a(d) = 5d - 3

a(a'(d))  = 5(\frac{d}{5} + \frac{3}{5}) - 3

a(a'(d))  = \frac{5d}{5} + \frac{15}{5} - 3

a(a'(d))  = d + 3 - 3

a(a'(d))  = d

Solving for: a'(a(d))

a'(a(d)) = a'(5d - 3)

Substitute 5d - 3 for d in a'(d) = \frac{d}{5} + \frac{3}{5}

a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}

Add fractions

a'(a(d)) = \frac{5d - 3+3}{5}

a'(a(d)) = \frac{5d}{5}

a'(a(d)) = d

Hence:

a(a'(d)) = a'(a(d)) = d

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3 years ago
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barxatty [35]

Answer:

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Step-by-step explanation:

8/72 = x/36

crossmultiply

8 x 36 = X x 72

288 = 72x

divide both sides by 72

288/72 = x

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<u>Answer:</u>

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