Answer:
![5\sqrt[4]{x}](https://tex.z-dn.net/?f=5%5Csqrt%5B4%5D%7Bx%7D)
or the fourth answer
Step-by-step explanation:
Apply the rule ![x^{\frac{m}{n}}=\sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%3D%5Csqrt%5Bn%5D%7Bx%5Em%7D)
to rewrite the exponentiation as a radical.
![5\sqrt[4]{x^1}](https://tex.z-dn.net/?f=5%5Csqrt%5B4%5D%7Bx%5E1%7D)
Anything raised to 1 is the base itself.
Answer =
Plz mark me brainliest, hope this helps.
n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
The number<span> is between integers, so it can't be an integer or a whole </span>number<span>. It's written as a ratio of two integers, so it's a </span>rational number<span> and not irrational. All</span>rational numbers<span> are real </span>numbers<span>, so this </span>number<span> is </span>rational<span> and real.</span>
Answer:
A. -5x = -23
Step-by-step explanation:
First you have to simplify the equation - 4(x - 5) + 8x = 9x - 3
-4x + 20 + 8x = 9x -3
9x - 4x = 20 + 3
5x = 23
=> equivalent to answer A.
<h3>Explanation:</h3>
1. PQ║TS, PQ ≅ TS, PT and QS are transversals to the parallel lines . . . given
2. ∠P ≅ ∠T . . . alternate interior angles at PT
3. ∠Q ≅ ∠S . . . alternate interior angles at QS
4. ΔPQR ≅ ΔTSR . . . ASA postulate
_____
You can use any pair of angles together with the sides PQ and TS. If you use the vertical angles and one of ∠T or ∠S, then you must invoke the AAS postulate for congruence, as the side is not between the two angles.
