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alexgriva [62]
4 years ago
9

How to resolve this ?

Mathematics
1 answer:
4vir4ik [10]4 years ago
6 0

Answer:

3: 6,9,12,15,18,21 and 24.

7: 14,21,28,35,42,49 and 56.

5: 10,15,20,25,30,35 and 40.

9: 18,27,36,45,54,63 and 72

4: 8,12,16,20,24,28 and 32.

Step-by-step explanation:

Given are the number at the beginning of each strings.

We need to write multiples of number on first light of string on rest of lights on the string.

3: 3\times 1= 3 (given)

3\times 2= 6\\3\times 3= 9\\3\times 4= 12\\3\times 5= 15\\3\times 6= 18\\3\times 7= 21\\3\times 8= 24

7: 7\times 1= 7 (given)

7\times 2= 14\\7\times 3= 21\\7\times 4= 28\\7\times 5= 35\\7\times 6= 42\\7\times 7= 49\\7\times 8= 56

5: 5\times 1= 5 (given)

5\times 2= 10\\5\times 3= 15\\5\times 4= 20\\5\times 5= 25\\5\times 6= 30\\5\times 7= 35\\5\times 8= 40

9: 9\times 1= 9 (given)

9\times 2= 18\\9\times 3= 27\\9\times 4= 36\\9\times 5= 45\\9\times 6= 54\\9\times 7= 63\\9\times 8= 72

4: 4\times 1= 4 (given)

4\times 2= 8\\4\times 3= 12\\4\times 4= 16\\4\times 5= 20\\4\times 6= 24\\4\times 7= 28\\4\times 8= 32

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