Answer:
False; this is the law of syllogism.
Step-by-step explanation:
Law of Detachment is:
1) p->q
2) p
------------------------
Conclusion: q
Law of syllogism is:
1) p->q
2) q->r
---------------------
Conclusion: p->r
Answer:
I think its answer A I think so
Answer:
the answer is c
Step-by-step explanation:hope this helps
Answer:
![\theta \approx 6.28n + 2.38, \quad n \in \mathbb{Z}](https://tex.z-dn.net/?f=%5Ctheta%20%5Capprox%206.28n%20%2B%202.38%2C%20%20%5Cquad%20%20n%20%5Cin%20%5Cmathbb%7BZ%7D)
or
![\theta \approx 6.28n + 0.76, \quad n \in \mathbb{Z}](https://tex.z-dn.net/?f=%5Ctheta%20%5Capprox%206.28n%20%2B%200.76%2C%20%5Cquad%20n%20%5Cin%20%5Cmathbb%7BZ%7D)
Considering ![\theta \in (0, 2\pi]](https://tex.z-dn.net/?f=%5Ctheta%20%5Cin%20%280%2C%202%5Cpi%5D)
![\theta \approx 2.38](https://tex.z-dn.net/?f=%5Ctheta%20%5Capprox%202.38)
or
![\theta \approx 0.76](https://tex.z-dn.net/?f=%5Ctheta%20%5Capprox%200.76)
Step-by-step explanation:
![\sin(\theta)=0.6892](https://tex.z-dn.net/?f=%5Csin%28%5Ctheta%29%3D0.6892)
We have:
![\sin (x)=a \Longrightarrow x=\arcsin (a)+2\pi n \text{ or } x=\pi -\arcsin (a)+2\pi n \text{ as } n\in \mathbb{Z}](https://tex.z-dn.net/?f=%5Csin%20%28x%29%3Da%20%5CLongrightarrow%20x%3D%5Carcsin%20%28a%29%2B2%5Cpi%20n%20%5Ctext%7B%20or%20%7D%20x%3D%5Cpi%20-%5Carcsin%20%28a%29%2B2%5Cpi%20n%20%5Ctext%7B%20as%20%7D%20n%5Cin%20%5Cmathbb%7BZ%7D)
Therefore,
![\theta= \arcsin (0.6892)+2\pi n, \quad n \in \mathbb{Z}](https://tex.z-dn.net/?f=%5Ctheta%3D%20%5Carcsin%20%280.6892%29%2B2%5Cpi%20n%2C%20%5Cquad%20n%20%5Cin%20%5Cmathbb%7BZ%7D)
or
![\theta = \pi -\arcsin (0.6892)+2\pi n, \quad n\in \mathbb{Z}](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Cpi%20-%5Carcsin%20%280.6892%29%2B2%5Cpi%20n%2C%20%5Cquad%20%20n%5Cin%20%5Cmathbb%7BZ%7D)
---------------------------------
![\theta \approx 6.28n + 2.38, \quad n \in \mathbb{Z}](https://tex.z-dn.net/?f=%5Ctheta%20%5Capprox%206.28n%20%2B%202.38%2C%20%20%5Cquad%20%20n%20%5Cin%20%5Cmathbb%7BZ%7D)
or
![\theta \approx 6.28n + 0.76, \quad n \in \mathbb{Z}](https://tex.z-dn.net/?f=%5Ctheta%20%5Capprox%206.28n%20%2B%200.76%2C%20%5Cquad%20n%20%5Cin%20%5Cmathbb%7BZ%7D)
First, you have to combine the 6x and the 10x you do this by subtracting 6x from each side. doing that you get....
-11=4x-51
then, you have to combine the -11 and the -51 you do this by adding 51 to each side. doing that you get....
40=4x
lastly, you need to divide each side by 4 to isolate the variable x. you get...
x=10