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2 years ago

Solve for h . -98 = -7 h h =

Mathematics

2 answers:

Fofino [41]2 years ago

8 0

Answer:

Step-by-step explanation:

Step 1:

- 98 = - 7h Equation

Step 2:

- 98 ÷ - 7 = h Divide on both sides

Answer:

h = 14

Hope This Helps :)

Svetlanka [38]2 years ago

6 0

Answer:

Step-by-step explanation:

Here you go mate

Step 1

-98=-7h Equation/Question

Step 2

-98=-7h Simplify

-98=-7h

Step 3

-98=-7h Divide both sides

answer

h=14

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stealth61 [152]

$\large\underline{\sf{Solution-}}$

We have to evaluate the given expression.

$\rm = \sqrt{ \dfrac{1 - \sin(x) }{1 + \sin(x) } }$

If we multiple both numerator and denominator by 1 - sin(x), then the value remains same. Let's do that.

$\rm = \sqrt{ \dfrac{[1 - \sin(x)][1 - \sin(x) ]}{[1 + \sin(x)][1 - \sin(x) ]} }$

$\rm = \sqrt{ \dfrac{[1 - \sin(x)]^{2}}{1- \sin^{2} (x) } }$

We know that:

$\rm \longmapsto { \sin}^{2}(x) + \cos^{2}(x) = 1$

$\rm \longmapsto \cos^{2}(x) = 1 - { \sin}^{2}(x)$

Therefore, the expression becomes:

$\rm = \sqrt{ \dfrac{[1 - \sin(x)]^{2}}{\cos^{2} (x)}}$

$\rm = \dfrac{1 - \sin(x)}{\cos(x)}$

$\rm = \dfrac{1}{\cos(x)} - \dfrac{ \sin(x) }{ \cos(x) }$

$\rm = \sec(x) - \tan(x)$

7 0

2 years ago

Read 2 more answers

How many 2/3 cup servings are there in 6 cups of fruit

scoray [572]

Answer:

9 cups

Step-by-step explanation:

6 ÷ 2/3

6/1 ÷ 2/3

6/1 x 3/2 = 18/2 = 9/1 = 9

3 0

3 years ago

The surface area of the cylinder

o-na [289]

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Male and female high school students reported how many hours they worked each week in summer jobs. The data is represented in th

mihalych1998 [28]

Question:

1. The females worked less than the males, and the female median is close to Q1.

2. There is a high data value that causes the data set to be asymmetrical for the males.

3. There are significant outliers at the high ends of both the males and the females.

4. Both graphs have the required quartiles.

Answer:

The correct option is;

1. The females worked less than the males, and the female median is close to Q1

Step-by-step explanation:

Based on the given data, we have;

For males

Minimum = 0

Q1 = 1

Median or Q2 = 20

Q3 = 25

Maximum = 50

For females;

Minimum = 0

Q1 = 5

Median or Q2 = 6

Q3 = 10

Maximum = 18

Therefore, the values of data that affect the statistical measures of spread and center are that

The females worked less than the males as such the statistical data for the females have less variability than the males in terms of interquartile range

Also the female median is very close to Q1, therefore it affects the definition of a measure of center.

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3 years ago

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3 years ago