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tatiyna
3 years ago
7

A website requires their users to create a password for their own account using numbers from 0-5, inclusive, non-repeatedly. The

password has to be at least 5-digit long, then how many possible ways are there for them to create their passwords?
Computers and Technology
2 answers:
zalisa [80]3 years ago
6 0
I don’t know because I don’t know what I do not know
galben [10]3 years ago
3 0

Answer:

720

Explanation:

You might be interested in
The greater the profit motive in an economic system , the greater the likelihood of a.Innovation b.Equity c.Security d.Governmen
xxMikexx [17]

Answer:

d. Government controlling the factors of production.

Explanation:

Businesses exist to make profit. There is requirement to provide value for money to the customers in order for a business to achieve success. When a business fails to provide good customer service and exists only to make profits they might fail. In such situation government intervenes to stop the monopoly and save the consumers from the mercy of business.

3 0
3 years ago
Purpose of this project is to increase your understanding of data, address, memory contents, and strings. You will be expected t
STALIN [3.7K]

Answer:

See explaination for the details

Explanation:

#Starting point for code/programm

main:

la $a0,newLine #Print a new line

li $v0,4

syscall

# Find the number of occurence of a string in the given sentence

la $a0,prompt1 # Prompt the user to enter the first string.

li $v0,4

syscall

li $v0, 8 # Service 8 = read input string

la $a0, fword

li $a1, 9

syscall

la $a0,prompt2 # Prompt the user to enter the second string.

li $v0,4

syscall

li $v0, 8 # Service 8 = read input string

la $a0, sword

li $a1, 9

syscall

# process first word

li $t4,0 # Intialize the couter to 0

la $t0,sstatement # Store the statement into $t0

nstart1: la $t1,fword # Store the search word into $t1

loop1: # loop1 finds the number of occurences

# of input word in the given statment

lb $t2,($t0) # Load the starting address(character) of

# sstatement into $t2

lb $t3,($t1) # Load the starting address of input word

# into $t3

beq $t3,'\n',inc_counter1

beqz $t3,inc_counter1 # If $t3 is null , exit loop and print output

beqz $t2,print_output1 # If $t2 is null , exit loop and print output

move $a0,$t2 # Convert $t2 to lower, if it is upper case

jal convert2lower

move $t2,$v0 # Store the return($v0) value into $t2

move $a0,$t3 # Convert $t3 to lower, if it is upper case

jal convert2lower

move $t3,$v0 # Store the return($v0) value into $t3

bne $t2,$t3,next_char1 # If both characters are not matched current

# character in the string, go to next character

addiu $t0,$t0,1 # otherwise, increment both indexes

addiu $t1,$t1,1

j loop1 # go to starting of the loop

next_char1:

la $t5,fword

bne $t5,$t1,nstart1

la $t1,fword # Store the input word into $t1

addiu $t0,$t0,1 # Increment the index to goto next character

j loop1 # go to starting of the loop

inc_counter1:

addi $t4,$t4,1 # Increment the frequency counter by 1

la $t1,fword # Store input word into $t1

j loop1 # go to starting of the loop

print_output1:

la $t0,fword

L1:

lb $a0,($t0)

beq $a0,'\n',exL1

jal convert2upper

move $a0,$v0

li $v0,11

syscall

addiu $t0,$t0,1

j L1

exL1:

la $a0,colon

li $v0,4

syscall

la $a0, dash

li $v0, 4

syscall

move $a0,$t4

li $v0,1

syscall # print new line

la $a0,newLine

li $v0,4

syscall

# process second word

li $t4,0 # Intialize the couter to 0

la $t0,sstatement # Store the statement into $t0

nstart2: la $t1,sword # Store the search word into $t1

loop2: # loop1 finds the number of occurences

# of input word in the given statment

lb $t2,($t0) # Load the starting address(character) of

# sstatement into $t2

lb $t3,($t1) # Load the starting address of input word

# into $t3

beq $t3,'\n',inc_counter2

beqz $t3,inc_counter2 # If $t3 is null , exit loop and print output

beqz $t2,print_output2 # If $t2 is null , exit loop and print output

move $a0,$t2 # Convert $t2 to lower, if it is upper case

jal convert2lower

move $t2,$v0 # Store the return($v0) value into $t2

move $a0,$t3 # Convert $t3 to lower, if it is upper case

jal convert2lower

move $t3,$v0 # Store the return($v0) value into $t3

bne $t2,$t3,next_char2 # If both characters are not matched current

# character in the string, go to next character

addiu $t0,$t0,1 # otherwise, increment both indexes

addiu $t1,$t1,1

j loop2 # go to starting of the loop

next_char2:

la $t5,sword

bne $t5,$t1,nstart2

la $t1,sword # Store the input word into $t1

addiu $t0,$t0,1 # Increment the index to goto next character

j loop2 # go to starting of the loop

inc_counter2:

addi $t4,$t4,1 # Increment the frequency counter by 1

la $t1,sword # Store input word into $t1

j loop2 # go to starting of the loop

print_output2:

la $t0,sword

L2:

lb $a0,($t0)

beq $a0,'\n',exL2

jal convert2upper

move $a0,$v0

li $v0,11

syscall

addiu $t0,$t0,1

j L2

exL2:

la $a0,colon

li $v0,4

syscall

la $a0, dash2

li $v0, 4

syscall

move $a0,$t4

li $v0,1

syscall

exit:

# Otherwise, end the program

li $v0, 10 # Service 10 = exit or end program

syscall

############################ subroutine - convert2lower #################################

convert2lower: # Converts a character(stored in $a0) to

# its lower case, if it is upper case

# and store the result(lower case) in $v0

move $v0,$a0

blt $a0,'A',return

bgt $a0,'Z',return

subi $v0,$a0,-32

return: jr $ra # Return the converted(lower case) character

############################## subroutine - convert2upper ##################################

convert2upper: # Converts a character(stored in $a0) to

# its upper case, if it is lower case

# and store the result(upper case) in $v0

move $v0,$a0

blt $a0,'a',return2

bgt $a0,'z',return2

addiu $v0,$a0,-32

return2: jr $ra # Return the converted(lower case) character

4 0
3 years ago
Write Python statements that correspond to the actions below and execute them (a) Assign integer value 3 to variable a. (b) Assi
snow_tiger [21]

Here is code in Python.

#integer value 3 assigned to variable a.

a=3

#integer value 4 assigned to variable v.

b=4

# the value of given expression a * a b *b will be assign to variable c .

c=(a*a)*(b*b)

Explanation:

First an integer value is assigned to variable "a".And then integer 4 is assigned to variable "b". Calculate the value of expression a*ab*b and assigned to variable "c". Here expression a*ab*b can also be written as (a*a)*(b*b).

5 0
3 years ago
What are some harmful outcomes that stem from internet anonymous?
beks73 [17]
This link should help u:

www.bbc.com/capital/story/20150309-the-danger-of-online-anonymity
7 0
3 years ago
Write a program with a method called passwordCheck to return if the string is a valid password. The method should have the signa
Ber [7]

Answer:

import java.util.regex.*;

import java.util.Scanner;

public class Password

{

  public static void main(String[] args) {

  Scanner input = new Scanner(System.in);

  System.out.println("Please enter the Password. \n");

  String passwordString = input.next();

  System.out.println(passwordCheck(passwordString));

  }

  public static boolean passwordCheck(String password){

  if(password.length()>=8 && password.matches("[a-z0-9A-Z]+")){

  return true;

  }

  else{

  return false;

  }

  }

}

Explanation:

The Java class "Password" is used by the program to make an instance of the password object and check its validity with the passwordChecker method defined within the Password class. The passwordChecker method only matches alphanumeric passwords, that is, passwords with alphabets and numbers. If a non-alphanumeric character is encountered, the boolean value false is returned.

6 0
3 years ago
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