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Taya2010 [7]
3 years ago
14

Solve for r rs / a - 3 = k

Mathematics
1 answer:
Jobisdone [24]3 years ago
6 0
You can isolate r to one side of the equation by dividing by adding three, dividing by s, multiplying by a and you get:

r=a(3+k)/s
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NEED HELP ASAP
Anika [276]

Answer:

Y=4x+9

Step-by-step explanation:

Use rise over run to find 2 points for the slope. B is as simple as looking where the line passes y.

6 0
3 years ago
Read 2 more answers
What is the solution to the equation?
Lisa [10]
3q + 5 = -2q + 20

add 2q to both sides.

5q + 5 = 20

subtract 5 to both sides.

5q = 15

divide 5 to both sides.

q = \frac{15}{5}

the answer is: q = 3 
5 0
3 years ago
1.find the sum. (3^3+5x^2+3x-7)+(8x-6x^2+6)<br> 2. Find the Difference: (8x-4x^2+3\)-(x^3+7x^2+3x-8)
vlada-n [284]

1.

(3^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=27\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=-x^2+11x+26

or if you mean (3x^3+5x^2+3x-7)+(8x-6x^2+6):

(3x^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=3x^3\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=3x^3-x^2+11x-1

2.

(8x-4x^2+3)-(x^3+7x^2+3x-8)=\\\\=\underline{8x}\ \underline{\underline{-\ 4x^2}}+3-x^3\ \underline{\underline{-\,7x^2}}\ \underline{-\,3x}+8=\\\\=-x^3-11x^2+5x+10

3 0
3 years ago
If there are 26 students in each third-grade class and 3 third-grade classes in the school, how many students will attend an ass
ddd [48]

Answer:

74

Step-by-step explanation:

26 • 3 = 78 - 4 = 74

8 0
3 years ago
who does the number, of zeros in the product of 8 and 5000 compara to the number of zeros in the factors ? explain.
mezya [45]
If one of the numbers we multiply (factors) has zeros at the end, and the other isn't a fraction: all those zeros will stay in the product.

But there might be additional zeros if the other numbers  in the factors (the numbers which aren't 0) mupliply  to  "end" in zero and this is the case here:

8*5=40.

so the product will be 40 and the zeros of the 5000:

40 000

the number of zeros in the product will be bigger than the number of zeros in the factors if the non-zero parts of the fractions multiply to a number with 0 at the end.
4 0
2 years ago
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