Answer:
Y=9x-21
Step-by-step explanation:
Given:
The graph of a function
.
To find:
The interval where
.
Solution:
From the given graph graph it is clear that, the function before x=0 and after x=3.6 lies above the x-axis. So,
for
and
.
The function between x=0 and x=3.6 lies below the x-axis. So,
for
.
Now,
For
, the graph of h(x) is above the x-axis. So,
.
For
, the graph of h(x) is below the x-axis. So,
.
For
, the graph of h(x) is below the x-axis. So,
.
Only for the interval
, we get
.
Therefore, the correct option is A.
The answer would be 71.45
Answer:
x=13,y=0
Step-by-step explanation:
We are given a system of equations

For equation 1,square all terms to reduce it
√x²+√y²=169
x+y=13
Make x the subject as required by the question to use substitution method
x=13-y
Plug x=13-y into eqn 2
3(13-y)+2y=39
39-3y+2y=39
39-y=39
y=39-39=0
Plug y=0 into equation 1
x+0=13
x=0