Question

Can anyone help me with this the last answer choice is wrong

Answer 1

Answer:

It's the 2nd one

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

for all x>6

x-6>0

$\frac{6x-x^2}{x^2-4x-12} \\=\frac{-x(x-6)}{x^2-6x+2x-12} \\=\frac{-x(x-6)}{x(x-6)+2(x-6)} \\=\frac{-x(x-6)}{(x-6)(x+2)} \\=\frac{-x}{x+2} \\by~dividing~by~x-6$