Given statement is False, if a light cost $3, it could be either Green or Yellow.
Converse: If the light bulb was Yellow, then the cost was $3 = True
Contrapositive makes both statements negative and switches the order of the original statement.
So something like: If the light bulb is not yellow, then the cost would not be $3 = False because two colors cost the $3.
Inverse makes both statements negative but keeps the same order.
Something like : If the light bulb did not cost$3 then the light bulb was not yellow = False because two colors cost the $3.
Let f(x) = p(x)/q(x), where p and q are polynomials and reduced to lowest terms. (If p and q have a common factor, then they contribute removable discontinuities ('holes').)
Write this in cases:
(i) If deg p(x) ≤ deg q(x), then f(x) is a proper rational function, and lim(x→ ±∞) f(x) = constant.
If deg p(x) < deg q(x), then these limits equal 0, thus yielding the horizontal asymptote y = 0.
If deg p(x) = deg q(x), then these limits equal a/b, where a and b are the leading coefficients of p(x) and q(x), respectively. Hence, we have the horizontal asymptote y = a/b.
Note that there are no obliques asymptotes in this case. ------------- (ii) If deg p(x) > deg q(x), then f(x) is an improper rational function.
By long division, we can write f(x) = g(x) + r(x)/q(x), where g(x) and r(x) are polynomials and deg r(x) < deg q(x).
As in (i), note that lim(x→ ±∞) [f(x) - g(x)] = lim(x→ ±∞) r(x)/q(x) = 0. Hence, y = g(x) is an asymptote. (In particular, if deg g(x) = 1, then this is an oblique asymptote.)
This time, note that there are no horizontal asymptotes. ------------------ In summary, the degrees of p(x) and q(x) control which kind of asymptote we have.
I hope this helps!
Answer:
(a) 0.70
(b) 0.40
Step-by-step explanation:
Mutually-exclusive events are those events which cannot occur together.
Consider that events X and Y are mutually exclusive.
P (X and Y) = 0
Here the two events can be defined as follows:
A = A can fix the busted computer
B = B can fix the busted computer
The information provided are as follows:
P (A) = 0.30
P (B) = 0.40
If A cannot, then there is a chance that her friend B can fix it.
The above statement suggest that the events A and B are mutually exclusive, i.e. if A can fix the computer then B does not have to and if cannot then only B will fix it.
That is, P (A and B) = 0.
(a)
Compute the probability it will be fixed by either A or B as follows:
P (A or B) = P (A) + P (B) - P (A and B)
= 0.30 + 0.40 - 0
= 0.70
Thus, the probability it will be fixed by either A or B is 0.70.
(b)
Compute the probability that if it is fixed it will be fixed by B as follows:
P (not A and B) = P (B) - P (A and B)
= 0.40 - 0
= 0.40
Thus, the probability that if it is fixed it will be fixed by B is 0.40.
The best and most correct answer among the choices provided by your question is the third choice. There are 1350 different ring selections.
It is because:
3*15*30 = 1,350
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
