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Neporo4naja [7]
3 years ago
13

Hey can anybody help me out

Mathematics
1 answer:
NikAS [45]3 years ago
6 0
You should be able to find the answer try using the tiger math app
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Using the digits 1 to 9, at most one time each, fill in the boxes so that the points make a parallelogram. Mathematically, use p
Lera25 [3.4K]

Answer:

\left\begin{array}{ccc}A\left( \boxed{3}  , \boxed{8} \right)&B\left( \boxed{9}  , \boxed{6} \right )\\\\C\left( \boxed{1}  ,  \boxed{4} \right)&D\left( \boxed{7}  ,  \boxed{2} \right )\end{array}\right

Step-by-step explanation:

The coordinates are:

\left\begin{array}{ccc}A\left( \boxed{3}  , \boxed{8} \right)&B\left( \boxed{9}  , \boxed{6} \right )\\\\C\left( \boxed{1}  ,  \boxed{4} \right)&D\left( \boxed{7}  ,  \boxed{2} \right )\end{array}\right

The parallelogram is attached below.

To verify if these coordinates form a parallelogram, we show that:

  • AB=CD; and
  • AC=BD

Using Distance Formula

AB = \sqrt{(6-8)^2+(9-3)^2} = \sqrt{(-2)^2+(6)^2} = \sqrt{40} $ units

CD = \sqrt{(2-4)^2+(7-1)^2} = \sqrt{(-2)^2+(6)^2} = \sqrt{40} $ units

AC = \sqrt{(8-4)^2+(3-1)^2} = \sqrt{(4)^2+(2)^2} = \sqrt{20} $ units

BD = \sqrt{(6-2)^2+(9-7)^2} = \sqrt{(4)^2+(2)^2} = \sqrt{20} $ units

Since AB=CD; and AC=BD, the coordinates A, B, C, and D form the vertex of a parallelogram.

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4 years ago
What is the value,in degree, of y
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I did the math.
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Using the quadratic formula we get

x_1 = 0.5\\x_2 = 2.04

Therefore the tennis ball is at least 15 feet above the ground from 0.5 seconds to 2.04 seconds

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Step-by-step explanation:

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