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3 years ago

The first term of the sequence is -15. what is the next term in the sequence?

Mathematics

1 answer:

Alenkinab [10]3 years ago

7 0

Answer:

-10

Step-by-step explanation:

minus 5 in each number

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To get a free meal at his favorite restaurant, Tom needs to spend $50 or more at the restaurant. He has already spent $30.25. Ho

MrRissso [65]

Answer:

50-30.25=19.75

Step-by-step explanation:

5 0

3 years ago

A company is considering the purchase of a new machine for $75,660. management predicts that the machine can produce sales of $2

nekit [7.7K]

The company is considering the purchase of a new machine for $75,660 (based on the available data), and the payback period is <u>24 years</u>.

<h3>What is the payback period?</h3>

The payback period is the time the company requires to recoup its investment for the new machine.

The payback period can be computed by dividing the investment cash outflows by the annual net cash inflows.

<h3>Data and Calculations:</h3>

Initial investment in new machine = $75,660

Annual depreciation expense = $4,600

Investment period = 10 years

Annual sales revenue = $20,000

Annual expenses = $16,800

Ne annual cash inflow = $3,200 ($20,000 - $16,800)

Payback period = 24 years ($75,660/$3,200)

Thus, since the payback period is <u>24 years</u>, while the investment period is 10 years, it sounds unwise for the company to continue the investment.

Learn more about the payback period at brainly.com/question/23149718

#SPJ1

3 0

1 year ago

Find the value of each expression when a=-2 b=-3 and c=5<br><br> 5a-(4b+6c)=?

Zepler [3.9K]

-10(-12+30)
-10 multiplied by 18
-180

7 0

3 years ago

Read 2 more answers

3x^2-12+(x-4)(2-x)-(x^2-4x+4)

bogdanovich [222]

Answer:

x² + 10x - 24

Step-by-step explanation:

3x² - 12 + (x - 4)(2 - x) - (x² - 4x + 4)

= 3x² - 12 + (2x - x² - 8 + 4x) - x² + 4x - 4

= 3x² - 12 + 2x - x² - 8 + 4x - x² + 4x - 4

= x² + 10x - 24

4 0

3 years ago

If m and n are the zeroes of the polynomial 6y 2 -7y – 2, find a polynomial whose zeroes are 1/m and 1/n

denis-greek [22]

Answer:

$y^2-\frac{7}{2}y+3$

Step-by-step explanation:

Given polynomial is,

6y² - 7y - 2

Fro the zeros of the given polynomial,

6y² - 7y - 2 = 0

6y² - 4y - 3y - 2 = 0

2y(3y - 2) - 1(3y - 2) = 0

(2y - 1)(3y - 2) = 0

(2y - 1) = 0

y = $\frac{1}{2}$

(3y - 2) = 0

y = $\frac{2}{3}$

Therefore, zeros of this polynomial are m = $\frac{1}{2}$ and n = $\frac{2}{3}$

If a polynomial has zeros as $\frac{1}{m}$ and $\frac{1}{n}$ then the zeros will be $\frac{3}{2}$ and 2.

Polynomial will be,

$(y-\frac{3}{2})(y-2)$

= $y(y-2)-\frac{3}{2}(y-2)$

= $y^2-2y-\frac{3}{2}y+3$

= $y^2-\frac{7}{2}y+3$

7 0

2 years ago