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adoni [48]
4 years ago
10

15.5 rounded to the nearest tenth

Mathematics
1 answer:
Degger [83]4 years ago
3 0
<span>The tenths place is to the right of the decimal point.</span>
In order to round u number to the nearest tenth, you should <span>to the right of the tenths place. Depending on this number you should determine if you will round up or stay the same (if it is bigger than 5 you will round up, if not it will stay the same).
In our case, the number is 15.5 so it is already rounded to the nearest tenth.

</span>
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Given that sec0=-37/12, what is the value of cot0, for pi/2&lt;0
Colt1911 [192]

Answer:

2nd option

Step-by-step explanation:

Using the identities

tan²θ + 1 = sec²θ

cotθ = \frac{1}{tan0}

Given

secθ = - \frac{37}{12} , then

tan²θ + 1 = (- \frac{37}{12} )² = \frac{1369}{144} ( subtract 1 from both sides )

tan²θ = \frac{1225}{144} ( take the square root of both sides )

Since \frac{\pi }{2} < θ < π and tanθ < 0 , then

tanθ = - \frac{35}{12}

Then

cotθ = \frac{1}{-\frac{35}{12} } = - \frac{12}{35}

5 0
3 years ago
An entrepreneur faces many bureaucratic and legal hurdles when starting a new business. The World Bank collects information abou
slamgirl [31]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

Rearranged data:

5, 5, 5, 5, 6, 7, 7, 7, 8, 12, 12, 13, 13, 15, 18, 18, 27, 28, 36, 48, 52, 60, 66, 94

Start time for Suriname = 694

Mean = ΣX / n

Mean = (567 + 694) / (24 + 1) = 1261 / 25 = 50.44

B.) median start Time for initial 24 values

0.5(n+1)th term

0.5(25) = 12.5th term

(13 + 13) / 2 = 13

C.) preferred measure of center for the distribution will be the median as it shapes well in the middle of the distribution. The mean is overestimated

d) Compute the quartiles (Q1, Q2, Q3), and find the IQR for these data. Are there outliers in the time to start a business data set? If so, identify and name any outliers.

Using calculator :

Lower quartile Q1 --> 7

Median Q2 --> 13

Upper quartile Q3 --> 42

IQR = (Q3 - Q1) = 42 - 7 = 35

OUTLIER:

Lower bound : Q1 - 1.5(IQR) ; 7 - 1.5(35) = - 45.5

Upper bound : Q3 + 1.5(IQR) = 42 + 1.5(35) = 94.5

Outlier : values below - 45.5 and above 94.5

Hence, Surimanes start time is the only Outlier.

e)

Standard deviation for 24 countries :

Standard deviation = sqrt[Σ(X - mean)^2 / (N - 1)]

Usibg calculator :

Standard deviation for the 24 countries is 23.83

f)

Standard deviation

5 0
3 years ago
(9mn-19^4n) - (8m^2+12m^4n+9mn
Alja [10]

Answer:

-19n^4 - 8m^2 - 12m^4n

Step-by-step explanation:

8m^2 + 12m^4n + 9mn

-

19n^4 9mn

------------------------------------------------------------------------

-19n^4 - 8m^2 - 12m^4n

6 0
3 years ago
What’s the value of DCB?<br> Pls help
amm1812

Answer:

78

Step-by-step explanation:

angle ACD + angle DCB = 180   (Angles on straight line)

4x + 2 + 3x + 3 = 180

7x + 5 = 180

7x = 180-5

7x = 175

x = 175 / 7

x = 25

angle DCB = 3x +3 = 3*25 + 3 = 75 +3 = 78

6 0
3 years ago
In October, Greg and Thomas had the same amount of money in their savings accounts. In November, Greg deposited $120 into his ac
Leona [35]
Let's give the variable that you are trying to answer for a symbol. Let's call it X.

X = the amount of money both Greg and Thomas had in October

We know that in November, Greg added $120 to his account. So, Greg's account has: X + 120

We know that Thomas increased the money in his account by 20%, so Thomas' account has: X + 0.2X, or 1.2X

We know that these two amounts are equal:
X + 120 = 1.2X

Solve for X:
X + 120 - X = 1.2X - X
120 = .2X
120 / .2 = .2X / .2
600 = X


5 0
4 years ago
Read 2 more answers
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