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Tems11 [23]
3 years ago
6

Which expressions are equivalent to (5⋅x)⋅3 ? Drag and drop the equivalent expressions into the box

Mathematics
2 answers:
dimaraw [331]3 years ago
4 0

Answer:

First option.

Third option.

Fourth option.

Step-by-step explanation:

For this exercise is important to remember that equivalent expression have the same value.

Then given the following expression provided in the exercise:

(5x)3

You can find equivalent expression by:

-  Changing the position of 3:

3(5x)     (This matches with the first option)

- Solving the multiplication indicated. Then:

(5x)3=15x      (This matches with the fourth option)

- Writting x3 inside the parentheses:

5(x3)     (This matches with the third option)

steposvetlana [31]3 years ago
4 0

Answer:

First option.

Third option.

Fourth option.

Step-by-step explanation:

I took the test online in K12 and when I reviewed it it said that the first, third, and fourth options are the correct answers. Have a nice day!

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Evaluate ( f/g)(x) if f(x) = 2x and g(x) = 3x – 2 when x = 2.
Evgen [1.6K]

Answer:

1

Step-by-step explanation:

(f/g)(x)

= \frac{f(x)}{g(x)}

= \frac{2x}{3x-2} ← substitute x = 2 into the expression

= \frac{2(2)}{3(2)-2}

= \frac{4}{6-2}

= \frac{4}{4}

= 1

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2 years ago
3. A Card is drawn from the deck and is not put back
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Answer:

dependent

Step-by-step explanation:

8 0
2 years ago
In a one-way ANOVA, what is the difference between the among-groups variance MSA and the within-groups variance MSW?
LuckyWell [14K]

Answer:

MSR=MSA=\frac{SSR}{k-1}

And MSE=MSW=\frac{SSE}{N-k}

The difference is that MSA takes incount the variation between the groups and the grand mean, and the MSW takes in count the variation within groups respect to the mean of each group .

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

If we assume that we have j groups and on each group from j=1,\dots,j we have n_j individuals on each group we can define the following formulas of variation:  

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SS_{between=Treatment}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2  

And we have this property  

SST=SS_{between}+SS_{within}=6750+8000=14750  

The degrees of freedom for the numerator on this case is given by df_{num}=k-1 where k  represent the number of groups.  

The degrees of freedom for the denominator on this case is given by df_{den}=df_{between}=N-k.  

And the total degrees of freedom would be df=N-1  

We can find the MSR=MSA=\frac{SSR}{k-1}

And MSE=MSW=\frac{SSE}{N-k}

The difference is that MSA takes incount the variation between the groups and the grand mean, and the MSW takes in count the variation within groups respect to the mean of each group .

And the we can find the F statistic F=\frac{MSR}{MSE}=

8 0
3 years ago
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