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Tems11 [23]
3 years ago
6

Which expressions are equivalent to (5⋅x)⋅3 ? Drag and drop the equivalent expressions into the box

Mathematics
2 answers:
dimaraw [331]3 years ago
4 0

Answer:

First option.

Third option.

Fourth option.

Step-by-step explanation:

For this exercise is important to remember that equivalent expression have the same value.

Then given the following expression provided in the exercise:

(5x)3

You can find equivalent expression by:

-  Changing the position of 3:

3(5x)     (This matches with the first option)

- Solving the multiplication indicated. Then:

(5x)3=15x      (This matches with the fourth option)

- Writting x3 inside the parentheses:

5(x3)     (This matches with the third option)

steposvetlana [31]3 years ago
4 0

Answer:

First option.

Third option.

Fourth option.

Step-by-step explanation:

I took the test online in K12 and when I reviewed it it said that the first, third, and fourth options are the correct answers. Have a nice day!

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Step-by-step explanation:


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3 years ago
1) Jo Anne needs to do a speech in her English class that can't be more than 4 minutes
djyliett [7]

Answer:

( 0 < y < 23 / 6 ) mins

Step-by-step explanation:

Solution:-

We will define a variable ( x ) as the time it took for Jo Anne to give her speech at home.

The time taken to give her speech must always be less than 4 minutes. We can express this mathematically using an inequality as follows:

                              ( 0 < x < 4 ) minutes

Jo Anne gave her speech which was 10 seconds less than the one she practised at home. We will convert the time in seconds to minutes as follows:

                             10 s * \frac{min}{60 s}  = \frac{1}{6} min

The time taken by Jo Anne to complete her speech in English class can be represented as:

                             y = x - 1/6

Using the range of time that Jo Anne could take in delivering her speech in the class would be:

                                    0 < x < 4

                            0 - 1/6 < y < 4 - 1/6

                            -1/6 < y < 23 / 6

Since time can not be less than zero. We correct the lower limit to " 0 " as follows:

                              ( 0 < y < 23 / 6 ) mins

   

7 0
3 years ago
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