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mart [117]
2 years ago
13

Compute the number of vinyl tiles, measuring 8 in. each side, needed to tile a kitchen measuring 24 ft. by 18 ft.

Mathematics
2 answers:
spayn [35]2 years ago
8 0

Answer: There are 972 tiles to cover the kitchen.

Step-by-step explanation:

Since we have given that

Dimensions of kitchen be

24\ ft\ by\ 18\ ft

Dimension of each tile = 8 inches

We have to find the number of tiles .

So, Number of tiles is given by

\frac{\text{Area of kitchen}}{\text{ Area of tile }}\\\\=\frac{24\times 12\times 18\times 12}{8\times 8}\\\\=\frac{62208}{64}\\\\=972

Hence, there are 972 tiles to cover the kitchen.

zepelin [54]2 years ago
4 0
972. Keep in mind the ratio of square feet to square inches is 144:1 as opposed to 12:1
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What is the midpoint of -5,2 and 1,5
ANEK [815]

Answer:(-2,3.5)

Step-by-step explanation: Add the endpoints and divide by two for the x-values and the y-values

4 0
3 years ago
A random sample of 70 printers discovered that 25 of them were being used in small businesses. find the 95% limit for the popula
kvasek [131]

Answer:

The sample proportion of printers used in small business is:

\hat{p}=\frac{25}{70}=0.3571

The 95% confidence interval for the population proportion of printers that are used in small businesses is:

\hat{p} \pm z_{\frac{0.05}{2}} \sqrt{\frac{\hat{p}(1-\hat{p})}{n} }

Where:

z_{\frac{0.05}{2}}=1.96 is the critical value at 0.05 significance level

\therefore 0.3571 \pm 1.96 \sqrt{\frac{0.3571(1-0.3571)}{70} }

         0.3571 \pm 0.1122

         \left ( 0.3571 - 0.1122, 0.3571 + 0.1122 \right)

         \left(0.245,0.469 \right)

Therefore, the 95% confidence interval for the population proportion of printers that are used in small businesses is (0.245 , 0.469)



7 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!
Brilliant_brown [7]

-2<em>x</em> + 6<em>y</em> = -38

3<em>x</em> - 4<em>y</em> = 32

To solve by elimination, multiply the top equation by 3 and the bottom equation by 2.

3(-2<em>x</em> + 6<em>y</em> = -38) --> -6<em>x</em> + 18<em>y</em> = -114

2(3<em>x</em> - 4<em>y</em> = 32) --> 6<em>x</em> - 8<em>y</em> = 64

Add the equations.

-6<em>x </em>+ 18<em>y</em> = -114

6<em>x</em> - 8<em>y</em> = 64

+_____________

0 + 10<em>y</em> = -50

10<em>y</em> = -50

<em>y</em> = -5

Substitute -5 for y into one of the original equations to find x.

3<em>x</em> - 4<em>y</em> = 32

3<em>x</em> - 4(-5) = 32

3<em>x</em> + 20 = 32

3<em>x</em> = 12

<em>x</em> = 4

Check work by plugging the <em>x</em>- and <em>y</em>-values into both of the original equations.

-2<em>x</em> + 6<em>y</em> = -38

-2(4) + 6(-5) = -38

-8 - 30 = 38

38 = 38


3<em>x</em> - 4<em>y</em> = 32

3(4) - 4(-5) = 32

12 + 20 = 32

32 = 32

Answer:

<em>x</em> = 4 and <em>y</em> = -5; (4, -5).

8 0
3 years ago
Read 2 more answers
It snows 2 inches an hour for 5 hours in Pittsburgh, PA. How many inches fell in total over those 5 hours?
amm1812

Answer:

10 inches

Step-by-step explanation:

6 0
2 years ago
What is the area of a triangle for one of the legs being 3in and the hypotenuse being 9in
elena55 [62]

The area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches is 12.727 square inches

<em><u>Solution:</u></em>

Given that to find area of a triangle for one of the legs being 3 inches and the hypotenuse being 9 inches

From given information,

Let "c" = hypotenuse = 9 inches

Let "a" = length of one of the leg of triangle = 3 inches

To find: area of triangle

<u><em>The area of triangle when hypotenuse and length of one side of triangle is given:</em></u>

A = \frac{1}{2} a \sqrt{c^2 - a^2}

Where, "c" is the length of hypotenuse

"a" is the length of one side of triangle

Substituting the given values we get,

A = \frac{1}{2} \times 3 \times \sqrt{9^2 - 3^2}

A =\frac{1}{2} \times 3 \times \sqrt{81-9}\\\\A =\frac{1}{2} \times 3 \times \sqrt{72}\\\\A =\frac{1}{2} \times 3 \times 8.48528\\\\A = \frac{1}{2} \times 25.45584\\\\A = 12.727

Thus area of triangle is 12.727 square inches

5 0
3 years ago
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