All categories

3 years ago

30 – 6w + 12 Solve for w

Mathematics

2 answers:

Artist 52 [7]3 years ago

8 0

Answer:

-6W + 42

Step-by-step explanation:

We need to organize this expression into groups of like terms, so we can combine them easier.

Numerical terms are commonly written last.

There is only one group of like terms:

30 , 12

Numerical terms in this expression have been added

damaskus [11]3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

An angle is created from points C, A, and B with vertex A. An arc is drawn from point A and intersects rays AC and AB. The inter

Minchanka [31]

Answer:

Bisecting an angle ⇒ answer a

Step-by-step explanation:

* Lets revise the steps of bisecting an angle

- How to construct a bisector of angle XYZ

1. Open the compass to any width, and place its pin at the angle’s

vertex Y and draw an arc cuts the two rays of the angle YX and YZ

at two points M and N respectively

2. Open the compass to another width and place its pin at M and draw

an arc between the two rays YX and YZ

3. Without changing the width of the compass place its pin at N and

draw another arc intersects the arc from M at point Q

4. Join YQ which is the bisector of angle XYZ

* Now lets compare these steps by the steps of the question

∵ The vertex of the angle ABC is A represented by Y

∵ The rays of the angle AC and AB represented by YX and YZ

∵ Points D , E represented by points M , N

∴ The construction is " Bisecting an angle "

7 0

3 years ago

find three consecutive odd integers such that the sum of the smallest number and middle number is 27 less than 3 times the large

katrin2010 [14]

A generic odd number can be written as

$2k+1,\quad k \in \mathbb{Z}$

Since there is an odd number every two numbers, three consecutive odd numbers will be

$2k+1,\quad 2k+3,\quad 2k+5$

Now let's make up the equations: the sum of the first two is

$(2k+1)+(2k+3)$

And 27 less than 3 times the largest is

$3(2k+5)-27$

These two must be the same, so we have

$(2k+1)+(2k+3)=3(2k+5)-27 \iff 4k+4 = 6k+30-27 \iff 4k+4=6k+3$

Subtracting 4k and 3 from both sides gives

$1=2k \iff k=\dfrac{1}{2}$

Which means that the problem has no solution.

To confirm this hypothesis, we can observe that, on the left hand side, we have the sum of two odd numbers, which is even

On the right hand side, we have an odd number, multiplied by 3 (still odd), take away 27 (still odd).

So, the left hand side is even, and the right hand side is odd. They can't be the same number.

7 0

3 years ago

How do I solve 24(x-1) = -6(4-x)+18

podryga [215]

So the right answer is 1.

Look at the attached picture

Hope it will help you...

Good luck on your assignment

~pragya

8 0

3 years ago

Read 2 more answers

Explain the steps for 0.000000001 in scientific notation

lawyer [7]

If you count the zeros it’s
one billionth

8 0

3 years ago

Read 2 more answers

Help. I've been staring at this math question for hours. I can't figure it out.

kogti [31]

All the numbers are tilted at a 90 degree angle, except for the number 4 which it tilted at an angle of 89 degrees, hoped this helps

4 0

3 years ago