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Irina-Kira [14]
3 years ago
7

What is the correct formula for ammonium carbonate !

Chemistry
1 answer:
AfilCa [17]3 years ago
4 0
(NH4)2CO3..... I just learned this so that why i know.
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Which part of modern atomic theory was first developed by John Dalton?
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C. one of the discoveries he made which gave him his fame in the scientific community was that the atom could not be destroyed
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3 years ago
The stopcock connecting a 3.06 L bulb containing methane gas at a pressure of 9.61 atm, and a 6.65 L bulb containing oxygen gas
Contact [7]

Answer : The final pressure in the system is 4.22 atm.

Explanation :

First we have to calculate the moles of methane.

PV=n_1RT

where,

P = pressure of gas = 9.61 atm

V = volume of gas = 3.06 L

T = temperature of gas = T

n_1 = number of moles of methane gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

(9.61atm)\times (3.06L)=n_1\times RT

n_1=\frac{29.4}{RT}

Now we have to calculate the moles of oxygen gas.

PV=n_2RT

where,

P = pressure of gas = 1.75 atm

V = volume of gas = 6.65 L

T = temperature of gas = T

n_2 = number of moles of oxygen gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

(1.75atm)\times (6.65L)=n_2\times RT

n_2=\frac{11.6}{RT}

Now we have to determine the final pressure in the system after mixing the gases.

P_{total}=(n_1+n_2)\times \frac{RT}{V_{total}}

where,

P_{total} = final pressure of gas = ?

V_{total} = final volume of gas = (3.06 + 6.65)L = 9.71 L

T = temperature of gas = T

R = gas constant

Now put all the given values in the ideal gas equation, we get:

P_{total}=(\frac{29.4}{RT}+\frac{11.6}{RT})\times \frac{RT}{9.71L}

P_{total}=4.22atm

Therefore, the final pressure in the system is 4.22 atm.

4 0
3 years ago
Which of the following would be considered a solution?
sineoko [7]
The answer is sugar in water because it is soluble in water
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3 years ago
Molarity is measured in
aniked [119]
Answer D moles per L
5 0
3 years ago
This is the chemical formula for talc Mg3(Si2O5)2(OH)2(the main ingredient in talcum powder):
Elena-2011 [213]

Answer:

0.022 mol O

Explanation:

Mg3(Si2O5)2(OH)2

We can see that 1 mol of this substance has 3 mol of Mg.

Oxygen altogether  is 5*2 (from (Si2O5)2) + 2(from(OH)2) = 10 +2 = 12

So, 1 mol of this substance has 12 mol oxygen.

So,  1 mol of this substance contains 3 mol Mg and  12 mol O, or

ratio Mg : O = 3 : 12 = 1 : 4

1 mol Mg ----- 4 mol O

0.055 mol Mg ---x mol O

x = 0.055*4/1 = 0.220 mol O

8 0
4 years ago
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