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egoroff_w [7]
4 years ago
6

What is first and second element of the periodic table?

Chemistry
2 answers:
stira [4]4 years ago
7 0
The elements on the periodic table are listed in increasing atomic number. 

Hydrogen is the first element, and has an A.N. of 1. Also, its very interesting how it doesn't need 8 valence electrons to be stable. 

The second element is Helium, which has an A.N (atomic number) of two. 
WINSTONCH [101]4 years ago
6 0

Hydrogen= First element,H

Helium=Second Element,He


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34.2 gram of sucrose is dissolved in 180 gram water. Calculate the number of hydrogen and oxygen atoms present in the solution.
Naddika [18.5K]

Explanation:

34.2g of C12H22O11 is dissolved in 180g of H20.

Molar mass of sucrose = 342g/mol

Moles of sucrose = 342 / 34.2 = 10 mol.

Molar mass of water = 18g/mol

Moles of water = 180 / 18 = 10 mol.

For hydrogen atoms, there are 22 * 10 in sucrose and 2 * 10 in water, which gives a total of 240.

For oxygen atoms, there are 11 * 10 in sucrose and 1 * 10 in water, which gives a total of 120.

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What happens when a substance undergoes a physical change? Some physical properties change, but the substance keeps its identity
elena55 [62]
Some physical properties change, but the substance keeps its identity.

When dealing with these kind of questions, understand that the keyword here is physical change. Thus, all options that says no physical properties change are WRONG. So this leaves us with only 2 answers left. However, this is a physical change, no chemical change. Thus, the substance will keep its identity and not change.

8 0
3 years ago
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Explanation:

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A gas takes up 50.0 L while at STP. How much volume will the same gas occupy if the pressure remains constant and the temperatur
kirill115 [55]

Answer:

69.6L

Explanation:

Using Charles law equation:

V1/T1 = V2/T2

Where;

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to this question, a gas takes up 50.0 L while at STP. A gas at STP will possess an initial temperature of 273K. Hence;

V1 = 50.0 L

V2 = ?

T1 = 273K

T2 = 380K

Using V1/T1 = V2/T2

50/273 = V2/380

CROSS MULTIPLY

380 × 50 = 273 × V2

19000 = 273V2

V2 = 19000 ÷ 273

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weqwewe [10]
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