Which geoiogic feature is most likey to from a mid

MgCl2 (aq) + K2SO4 (aq) --> 2KCl (aq) + MgSO4 (s)

vova2212 [387]

Answer:

$\boxed {\boxed {\sf 9.6 \ mol \ KCl}}$

Explanation:

We must use stoichiometry to solve this, which is the calculation of reactants and products in a reaction using ratios.

Let's analyze the reaction given.

$MgCl_2 _{(aq)} + K_2SO_4 _{(aq)} \rightarrow 2KCl _{(aq)} + MgSO_4 _{(s)}$

Now, look at the coefficients, or numbers in front of the molecule formulas. If there isn't a coefficient, then a 1 is implied.

We want to find how many moles of potassium chloride (KCl) are produced from 4.8 moles of magnesium chloride (MgCl₂). Check the coefficients for these molecules.

MgCl₂: no coefficient= coefficient of 1
KCl: coefficient of 2

The coefficient represents the number of moles. Therefore, 1 mole of magnesium chloride produces 2 moles of potassium chloride. We can set up a ratio using this information.

$\frac { 1 \ mol \ MgCl_2} {2 \ mol \ KCl}$

Multiply by the given number of moles of magnesium chloride: 4.8

$4.8 \ mol \ MgCl_2 *\frac { 1 \ mol \ MgCl_2} {2 \ mol \ KCl}$

Flip the ratio so the moles of magnesium chloride cancel out.

$4.8 \ mol \ MgCl_2 *\frac {2 \ mol \ KCl} { 1 \ mol \ MgCl_2}$

$4.8 *\frac {2 \ mol \ KCl} { 1 \ } }$

$4.8 * {2 \ mol \ KCl}$

$9.6 \ mol \ KCl$

<u>9.6 moles of potassium chloride are produced </u>from 4.8 moles of magnesium chloride.

4 0

2 years ago

A student uses a diagram to show the scale sizes of the planets. Which planet’s diameter would be approximate the distance of th

aliya0001 [1]

The correct answer is Mercury

Explanation:

In a circular object or spherical object such as a planet, the diameter is calculated by drawing a straight line from one side of the sphere to the other. This measure is the double of the radius (distance from the center to any side). In the case of planets, these differ not only in properties but also in size, which makes them have different diameters.

For example, the diameter of Earth is approximately 12,700 km, while the diameter of Jupiter (the largest planet) is almost 143,000 km. In this context, the planet with a diameter that is approximately the same that the distance from one coast to the other in the U.S. is Mercury because the diameter of this planet is almost 4879 kilometers and the distance from the West coast to the East coast is approximately 4828 kilometers, although this distance varies depending on the location.

6 0

3 years ago

PLEASE PLEASE HELP ME!! I WILL BRAINLIST YOU!! A 28.0 g sample of N2 is in a rigid 4.50 L container at 32 °C. Calculate the pres

chubhunter [2.5K]

Answer:

P=4184.36 torr

Explanation:

For this problem we can use the idea gas law,

$PV=nRT$

where P is pressure, V is volume, n is moles of substance, R is the constant, and T is temperature, We will need to manipulate it and a couple values so that we can get our answer in torr. To do this, let's rearrange the equation to solve for P.

$P=\frac{nRT}{V}$

Next, let's convert T (32) to kelvin. To do this, add 273 to the value.

$32+273=305$

Next, let's convert 28g of N2 to moles of N2. To do this, divide 28 by the molar mass of N2 (28.02)

$\frac{28.0}{28.01} \\=.99$ moles of N2

Next, we need to find out what value of R we need to use. Because you want your answer in torr, we will need to use the value of

$R=62.36\frac{torr}{mol*K}$

Now that we have all of our values, let's plug them into the equation (I'll be excluding units for simplicity but they cancel out to leave units of torr in the answer)

$P=\frac{(.99)(62.36)(305)}{4.50}\\P=4184.36$

P=4184.36 torr

<em>Very briefly</em>, I don't know what your periodic table looks like, but mine has nitrogen's molar mass as 14.01. If you have a different mass of nitrogen, this pretty drastically impacts the value. For example, if your nitrogen's molar mass was rounded to 14.0 (making N2 28g) then it would be one mole instead of .99 moles, raising the answer to 4228.70 torr. If you have any different values just plug them in in their proper spots. A similar concept applies to the Kelvin conversion.

6 0

2 years ago

These allow electricity to flow easily through them (think copper and aluminum).

Naddika [18.5K]

Answer:

conductors

Explanation:

4 0

3 years ago

How did Rutherford's gold foil experiment show that Thomson's plum pudding model of the atom was

Ket [755]

Answer:

He blasted alpha rays at the gold foils. The Alpha rays are charged positive. When he blasted them the protons deflected and changed the course of them and the electrons surrounding the atom let them through. In the plum pudding model they were supposed to be sprinkled on which was clearly wrong according to that experiment.

Explanation:

6 0

3 years ago