Question

Can someone help me with this system of equations

Answer 1

Y = $\frac{1}{2}$x + 3
y = x - 4

Since both equations are equal to y, you can set the two values equal to each other and solve for x.

$\frac{1}{2}$x + 3 = x - 4   Multiply both sides by 2
x + 6 = 2x - 8   Add x to both sides
6 = 3x - 8   Add 8 to both sides
14 = 3x   DIvide both sides by 3
4$\frac{2}{3}$ = x

Now, plug the x value into one of the original equations, I'll plug it into y = x - 4.

y = x - 4   Plug in the x value 
y = 4$\frac{2}{3}$ - 4   Subtract
y = $\frac{2}{3}$

x = 4$\frac{2}{3}$ and y = $\frac{2}{3}$