Sandys friends ate 0, 2, 3, 4, 6, 6, and 7 pretzels. Sandy says the mean of the data is 4. Is Sandy correct?

Mathematics

2 answers:

diamong [38]3 years ago

7 0

If sandys friends ate 0, 2, 3, 4, 6, 6, and 7 pretzels, the mean of the data would be 4. So yes sandy is correct.

natka813 [3]3 years ago

4 0

Yes she is correct because if you add up all the numbers you get 28 then you divide that number by how many numbers there are so 7 and you get 4.

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Need help<br> Question in the screenshot below<br> NO spam<br> Please show your work

Alja [10]

<h3>Answer: x = 6</h3>

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Work Shown:

$\log_{4}(x+10)+\log_{4}(x-2)=\log_{4}(64)\\\\\log_{4}\left((x+10)(x-2)\right)=\log_{4}(64)\\\\(x+10)(x-2)=64\\\\x^2-2x+10x-20=64\\\\x^2-2x+10x-20-64=0\\\\$

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x = 6 works as a solution however

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ratelena [41]

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According to a 2018 survey by Bankrate, 20% of adults in the United States save nothing for retirement (CNBC website). Suppose t

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Answer:

0.5981 = 59.81% probability that three or less of the selected adults have saved nothing for retirement

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they save nothing for retirement, or they save something. The probability of an adult saving nothing for retirement is independent of any other adult. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$