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Mariana [72]
3 years ago
13

The population of the Wallingfried neighborhood has been growing steadily since 1981. In 1988, the population was 36100 people.

In 1994, it was 43900 people.
Find an equation in the form y=mx+b, where x is the number of years past 1981 and y is the population of Wallingfrie.
Mathematics
1 answer:
vovikov84 [41]3 years ago
4 0

Answer:

y=1300x+27000

Step-by-step explanation:

given that the population of the Wallingfried neighborhood has been growing steadily since 1981.

In 1988,the population was 36100 people. In 1994, it was 43900 people.

x is the number of years past 1981 and y , the population of Wallingfrie.

we have two points on the line as

when = 13, y = 43900

and when x = 7, y =36100

i.e. (13,43900) and (7,36100) lie on the line

Using two point formula we get the line as

\frac{y-36100}{43900-36100} =\frac{x-7}{13-7} \\y-36100 =1300 (x-7)\\y =1300x +27000

is the equation of the line

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If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c
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Given:

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\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}

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Final Answer:

The option D is correct.

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