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Whitepunk [10]
3 years ago
13

Starting at home Michael travel uphill to the gift store for 24 minutes after 10 mph you can travel back home along the same pat

h down hill at a speed of 30 mph what is his average speed for the entire trip from home to the gift store and back
Mathematics
1 answer:
VladimirAG [237]3 years ago
6 0

The average speed for the entire trip from home to the gift store and back is 15 miles per hour

<em><u>Solution:</u></em>

Given that, Starting at home Michael travel uphill to the gift store for 24 minutes after 10 mph

1 hour = 60 minutes

24\ minutes = \frac{24}{60}\ hour

You can travel back home along the same path down hill at a speed of 30 mph

<em><u>The distance is given as:</u></em>

distance = speed \times time

<em><u>Uphill distance:</u></em>

Uphill\ Distance = 10 \times \frac{24}{60}  = 4 \text{ miles }

The downhill distance will also be same 4 miles at a speed of 30 mph

<em><u>Find the time taken for down trip</u></em>

time = \frac{4}{30} = 0.133

Thus, time taken for downtrip = 0.133 hours

Total\ time\ taken = \frac{24}{60} + 0.133\\\\Total\ time\ taken =0.533\ hours

Total distance traveled = 4 miles + 4 miles = 8 miles

<em><u>The average speed is given by formula:</u></em>

\text{Average Speed } = \frac{\text{Total distance traveled}}{\text{Total time taken}}

<em><u>Substituting the values we get,</u></em>

Average\ speed = \frac{8}{0.533} = 15.009 \approx 15

Thus average speed for the entire trip from home to the gift store and back is 15 miles per hour

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Step-by-step explanation:

<em>Step(i)</em>:-

<em>Given sample size 'n' =300</em>

Given data  random sample of 300 attendees of a minor league baseball game, 182 said that they bought food from the concession stand.

<em>Given sample proportion </em>

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<em>90% confidence interval for the proportion is determined by</em>

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(0.6066 - 1.645\sqrt{\frac{0.6066(1-0.6066)}{300} }  ,0.6066+1.645\sqrt{\frac{0.6066(1-0.6066)}{300} })

(0.6066 -  0.0463  ,0.6066 +  0.0463)

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<u>final answer</u>:-

<em>90% confidence interval for the proportion of fans who bought food from the concession stand</em>

(0.5603,0.6529)

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