Look at one of the vertices of the heptagon where two squares meet. The angles within the squares are both of measure 90 degrees, so together they make up 180 degrees.
All the angles at one vertex must clearly add up to 360 degrees. If the angles from the squares contribute a total of 180 degrees, then the two remaining angles (the interior angle of the heptagon and the marked angle) must also be supplementary and add to 180 degrees. This means we can treat the marked angles as exterior angles to the corresponding interior angle.
Finally, we know that for any convex polygon, the exterior angles (the angles that supplement the interior angles of the polygon) all add to 360 degrees (recall the exterior angle sum theorem). This means all the marked angles sum to 360 degrees as well, so the answer is B.
Answer: The missing statements are,
In first blank: ∠2≅∠1
In second blank: AC≅AC
In third blank: Reflexive
Step-by-step explanation:
Since, The hypotenuse angle theorem states that if the hypotenuse and an acute angle of one right triangle are congruent to the hypotenuse and an acute angle of another right triangle, then the two triangles are congruent to each other.
Here, given:
∠D and ∠B are right angles.
DC ║ AB
Prove: Δ ADC ≅ Δ CBA
Statement Reason
1.∠D and ∠B are right angles 1. Given
2. ∠2 ≅ ∠1 2. If lines are parallel then interior angles
are equal
3. AC≅AC 3. Reflexive
4.Δ ADC ≅ Δ CBA 4. Hypotenuse angle theorem
Answer:
k = 73
Step-by-step explanation:
The sum of all the angles in a triangle is 180 degrees.
62
° + k + 45
° = 180
Solve the equation for k
Add 62
° and 45
°
k + 107 = 180
Move all terms not containing C to the right side of the equation.
Subtract 107 from both sides of the equation.
k = 180 − 107
Subtract
k = 73
V= piR^2(h)
6283=pi(10^2)(h)
6283=pi(100)h
height = 6283/(pi(100))
then round to the nearest inch
Answer:
hjd
Step-by-step explanation:
