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suter [353]
3 years ago
5

Solve the system using multiplication for the linear combination method.

Mathematics
1 answer:
zysi [14]3 years ago
5 0
(2,3) is your answer for the equation
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The pieces of a puzzle are placed half by Giulio, one fifth by Marco and Fabrizio in equal parts, while Michele arranges on the
denis23 [38]

Answer:

Not exactly sure but I think it should be 30 pieces

Step-by-step explanation:

3 0
1 year ago
If n is a positive integer and the product of all integers from 1 to n, inclusive, is a multiple of 990, what is the least possi
blagie [28]

Answer:

B. 11

Step-by-step explanation:

When n = 11

The product of 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 and 11 is 39,916,800

39,916,800 is a multiple of 990

3 0
3 years ago
What are the steps to solving this limit?
patriot [66]

Answer:

lim(x---->0) = -5

Step-by-step explanation:

first: sin(x-π/2)= -cosx

so the equation will be :

lim(x---->0) = [-6cos(ax)-1}/cosx

solve :

lim(x---->0) =  [-(6cos(a(0))-1}/cos(0)

cos0=1

lim(x---->0)=(-(6(1)-1)/1

lim(x---->0)=-6+1/1

lim(x---->0)=-5

6 0
3 years ago
Read 2 more answers
Find the value of c that makes the expression a perfect square trinomial.<br><br> x2 + 4x + c
masha68 [24]

the value of c that makes the expression a perfect square binomial is c=4 .

<u>Step-by-step explanation:</u>

Here we have , an expression x2 + 4x + c or , x^2 + 4x + c . We need to find  the value of c that makes the expression a perfect square binomial. Let's find out:

We have ,  x^2 + 4x + c

⇒ x^2+4x+c

⇒ x^2+2(2)x+c

Now , we know that (a+b)^2=a^2+2(a)(b)+b^2

Comparing above equation  , to  x^2+2(2)x+c we get ;

⇒  x^2+2(2)x+c            { c=2^2  }

⇒  x^2+2(2)x+2^2

⇒  (x+2)^2

Therefore , the value of c that makes the expression a perfect square binomial is c=4 .

7 0
3 years ago
2x - 6 = 0 and 2y = 10. Find 3^x/3^y.
pshichka [43]

Answer:

\dfrac{1}{9}

Step-by-step explanation:

2x - 6 = 0

\implies 2x = 6

\implies x=3

2y = 10

\implies y=5

\dfrac{3^x}{3^y}=\dfrac{3^3}{3^5}=\dfrac{1}{3^2}=\dfrac{1}{9}

7 0
2 years ago
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