Solve the system using multiplication for the linear combination method.

If the actual distribution of tusk lengths does not match the ones predicted with the H-W equation, it may indicate that natural

Anna [14]

Answer:

See explanation below

Step-by-step explanation:

It depends on what null hypothesis is under consideration.

One of the most common null hypothesis that are subject of study in a given statistical model is the mean predicted by the model.

In this case, the scientist probably observed that the mean of tusk lengths she obtained in a sample did not match the one predicted with the H-W equation.

So, she decided to perform a statistical study by collecting random samples and measuring the tusk lengths to determine a new possible mean and contrast it against the one predicted by the H-W equation.

Let's call M the mean predicted by the H-W equation, and S the mean obtained by the scientist.

If M different of S and the p-value is 0.021, that means that there is at most 2.1% of probability that the difference between M and S could be due to a random sampling error.

It should be kept in mind that the p-value does not represent the probability that the scientist is wrong.

7 0

3 years ago

(2y + 14.6m + 3.8) – (34.8m + 15.6 + 2y) simplified

Scorpion4ik [409]

20.2m-11.8
Incase your wondering what happened to the y it got canceled out because they were equal on both sides.

3 0

4 years ago

A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave

erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, $L$ = 120 cm

Its wavelength $\lambda_1$ = 480 cm

$\lambda_2$ = 160 cm and $\lambda_3$ = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

The fundamental wavelength of a pipe which is open at both ends is 2L.
The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ $4L=4(120)=480\ cm$

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒ $\lambda_2=\frac{4L}{3}$ ⇒ $\lambda_3=\frac{4L}{5}$

⇒ $\lambda_2=\frac{4(120)}{3}$ ⇒ $\lambda_3=\frac{4(120)}{5}$

⇒ $\lambda_2=\frac{480}{3}$ ⇒ $\lambda_3=\frac{480}{5}$

⇒ $\lambda_2=160\ cm$ ⇒ $\lambda_3=96\ cm$

So the pipe is open at one end and closed at one end .

6 0

3 years ago

Three less than a number x is more than 15. an inequality that represents this word sentence is

Alina [70]

Answer:

x - 3 > 15

Step-by-step explanation:

7 0

2 years ago

The blackpoll warbler migrates 2,376 miles, stops, and then flies another 3,289 miles to reach its destination. The arctic tern

Gnoma [55]

The total migration for the Blackpoll Warbler is 5,665 miles.

The total migration for the Arctic Tern is 22,010.

Therefore the difference between the two is

22,010 - 5,665 = 16,345 miles

4 0

3 years ago