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Iteru [2.4K]
3 years ago
6

A 2.2 kg ball is attached to a ceiling by a string. The distance from the ceiling to the center of the ball is 1.06 m, and the h

eight of the room is 3.00 m. What is the gravitational potential energy associated with the ball relative to the ceiling?
Physics
1 answer:
Veronika [31]3 years ago
3 0

Answer:

U=-22.85J

Explanation:

The potential energy associated with a body (m) located at a given height (h) above a reference point is defined as:

U=mgh

At the reference point the potential energy is zero. In this case the body is below the reference point (the ceiling), therefore, the value of h is negative:

U=2.2kg*9.8\frac{m}{s^2}*(-1.06m)\\U=-22.85J

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In the diagram, the arrow shows the movement of electric
Hoochie [10]

Answer:

So we want to know what causes the electric charges to flow from one end of the battery to the other like the picture shows. In the battery we have a positive and a negative charge that are separated. They give an electric potential difference also known as voltage. The voltage causes the charge (electrons) to move from the negative pole to the positive pole. That is called the electron flow and that is what is what is actually happening in the electric circuit. The image shows that the current flows from the positive pole to the negative. That is called "conventional current" and it is a matter of convention. Both are caused by the difference in electric potential. So the correct answer is C.  

7 0
3 years ago
What is the speed over the ground of a mosquito flying 2 m/s relative to the air against a 2 m/s headwind?
salantis [7]

We have that the speed over the ground of a mosquito flying 2 m/s relative to the air against a 2 m/s headwind is

X=0m/s

From the question we are told that

mosquito flying 2 m/s

against a 2 m/s headwind

Generally

The speed over the ground is the Flight Speed minus resistance speed

Generally the equation for the  speed over the ground  is mathematically given as

X=Flight Speed-resistance speed

Therefore

X=2-2

X=0m/s

For more information on this visit

brainly.com/question/22271063?referrer=searchResults

8 0
3 years ago
Read 2 more answers
A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surfac
Sedbober [7]

Answer:

v = 1.2 m/s

Explanation:

The wavelength of the waves is given as the horizontal distance between the crests:

λ = wavelength = 5.5 m

Now, the time period is given as the time taken by boat to move from the highest point again to the highest point. So it will be equal to twice the time taken by the boat to travel from highest to the lowest point:

T = Time Period = 2(2.3 s) = 4.6 s

Now, the speed of the wave is given as:

v = f\lambda

where,

v= speed of wave = ?

f = frequency of wave = \frac{1}{T} = \frac{1}{4.6\ s} = 0.217\ Hz

Therefore,

v = (0.217\ Hz)(5.5\ m)\\

<u>v = 1.2 m/s</u>

5 0
3 years ago
The temperature of water in a beaker is 45°C. What does this measurement represent?
Tasya [4]

Answer:

the average kinetic energy of water particles - C.

8 0
3 years ago
Write equations for both the electric and magnetic fields for an electromagnetic wave in the red part of the visible spectrum th
NeTakaya

Answer:

Explanation:

General equation of the electromagnetic wave:

E(x, t)= E_0sin[\frac{2\pi}{\lambda}(x-ct)+\phi ]

where

\phi = Phase angle, 0

c = speed of the electromagnetic wave, 3 × 10⁸

\lambda = wavelength of electromagnetic wave, 698 × 10⁻⁹m

E₀ = 3.5V/m

Electric field equation

E(x, t)= 3.5sin[\frac{2\pi}{6.98\times10^{-7}}(x-3\times 10^8t)]\\\\E(x, t)= 3.5sin[{9 \times 10^6}(x-3\times 10^8t)]\\\\E(x, t)= 3.5sin[{9 \times 10^6x-2.7\times 10^{15}t)]

Magnetic field Equation

B(x, t)= B_0sin[\frac{2\pi}{\lambda}(x-ct)+\phi ]

Where B₀= E₀/c

B_0 = \frac{E_0}{c} = \frac{3.5}{3\times10^8}=1.2 \times 10^{-8}T

B(x, t)= 1.2\times10^{-8}sin[\frac{2\pi}{6.98\times10^{-7}}(x-3\times 10^8t)]\\\\B(x, t)= 1.2\times10^{-8}sin[{9 \times 10^6}(x-3\times 10^8t)]\\\\B(x, t)= 1.2\times10^{-8}sin[{9 \times 10^6x-2.7\times 10^{15}t)]

6 0
3 years ago
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