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3 years ago

When the temperature of an object increases, what happens to the kinetic energy of the particles in the object?

1 answer:

3 0

When the average kinetic energy of the particles in the object increases, we sense and measure that change as an increase in the object's temperature.

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A plastic film moves over two drums. During a 4-s interval the speed of the tape is increased uniformly from v0 = 2ft/s to v1 =

Ratling [72]

Answer:

Question 1)

a) The speed of the drums is increased from 2 ft/s to 4 ft/s in 4 s. From the below kinematic equations the acceleration of the drums can be determined.

$v_1 = v_0 + at \\4 = 2 + 4a\\a = 0.5~ft/s^2$

This is the linear acceleration of the drums. Since the tape does not slip on the drums, by the rule of rolling without slipping,

$v = \omega R\\a = \alpha R$

where α is the angular acceleration.

In order to continue this question, the radius of the drums should be given.

Let us denote the radius of the drums as R, the angular acceleration of drum B is

α = 0.5/R.

b) The distance travelled by the drums can be found by the following kinematics formula:

$v_1^2 = v_0^2 + 2ax\\4^2 = 2^2 + 2(0.5)x\\x = 12 ft$

One revolution is equal to the circumference of the drum. So, total number of revolutions is

$x / (2\pi R) = 6/(\pi R)$

Question 2)

a) In a rocket propulsion question, the acceleration of the rocket can be found by the following formula:

$a = \frac{dv}{dt} = -\frac{v_{fuel}}{m}\frac{dm}{dt} = -\frac{13000}{2600}25 = 125~ft/s^2$

b) $a = -\frac{v_{fuel}}{m}\frac{dm}{dt} = - \frac{13000}{400}25 = 812.5~ft/s^2$

5 0

4 years ago

NEED HELP PLEASE 15 POINTS PLEASEE NEED HELP

Ostrovityanka [42]

Answer:

I wish I knew

Explanation:

5 0

3 years ago

Read 2 more answers

Liquid water at 120 kPa enters a 7-kW pump where its pressure is raised to 5.6 MPa. If the elevation difference between the exit

ziro4ka [17]

Answer:

The answer is given below

Explanation:

Things provided in the statement:

Pressure P1 = 120 kPa and P2 = 5.6 MP or 5600 kPa

Power, W = 7 kW

Elevation difference = ∆z = 10 m

Mass of flow = m˙

So potential energy changes may be significant

Specific volume of water V= 0.001 m³/kg

Now putting the values in the formula

Power, W = m˙ x V (P1 - P2) + m˙ x g x ∆z

7 = m˙ x 0.001 (5600 - 120 ) + m˙ x 9.8 x 10 x (1 kJ/kg/ 1000 m^2/s^2)

7 = m˙ x 5.48 + m˙ x 0.098

7 = m ˙x 5.38

m˙ = 7/5.38

So mass flow m˙ = 1.301 kJ/s

8 0

3 years ago

If you walk along a log floating on a lake why does the log move in the opposite direction?

aivan3 [116]

HERE'S YOUR ANSWER: 

•Since the log is stationary and you are moving beside the log, it seems to move in the opposite direction from your point of view, because from your perspective u are stationary and the log is moving. If you were to stop moving the log would also stop moving.

HOPE IT HELPS...

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3 years ago

One of the explorers is able to jump a maximum distance of 19.5 m with an initial speed of 2.80 m/s. Find the gravitational acce

BlackZzzverrR [31]

Answer:

0.2 m/s^2

Explanation:

Maximum distance, h = 19.5 m

initial speed, u = 2.80 m/s

final speed, v = 0 m/s

Let the gravitational acceleration is a.

Use third equation of motion

$v^{2}=u^{2}-2\times a\times h$

$0^{2}=2.80^{2}-2\times a\19.5$

$2\times a\19.5=7.84$

a = 0.2 m/s^2

Thus the gravitational acceleration on the exoplanet is 0.2 m/s^2

8 0

3 years ago