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miskamm [114]
3 years ago
13

The temperature of water in a beaker is 45°C. What does this measurement represent?

Physics
1 answer:
Tasya [4]3 years ago
8 0

Answer:

the average kinetic energy of water particles - C.

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Please Help Me
JulijaS [17]

1. a=Δv/Δt=(v-vo)/t=(0-25)/5=-25/5=-5 m/s²

The "-" sign shows us that the car has a slow motion


2.a=Δv/Δt=(v-vo)/t=(10-0)/4=10/4=2,5 m/s²


3.they do not have acceleration because they go at constant speed


7 0
3 years ago
Explain the difference between an electrically charged and a neutral object
Stella [2.4K]

An electrically charged element is called an "ion". A neutral element is an atom.

7 0
3 years ago
A 3.06kg stone is dropped from a height of 10.0m and strikes the ground with a velocity of 7.00m/s. What average force of air fr
xxTIMURxx [149]
<span>22.5 newtons. First, let's determine how much energy the stone had at the moment of impact. Kinetic energy is expressed as: E = 0.5mv^2 where E = Energy m = mass v = velocity Substituting known values and solving gives: E = 0.5 3.06 kg (7 m/s)^2 E = 1.53 kg 49 m^2/s^2 E = 74.97 kg*m^2/s^2 Now ignoring air resistance, how much energy should the rock have had? We have a 3.06 kg moving over a distance of 10.0 m under a force of 9.8 m/s^2. So 3.06 kg * 10.0 m * 9.8 m/s^2 = 299.88 kg*m^2/s^2 So without air friction, we would have had 299.88 Joules of energy, but due to air friction we only have 74.97 Joules. The loss of energy is 299.88 J - 74.97 J = 224.91 J So we can claim that 224.91 Joules of work was performed over a distance of 10 meters. So let's do the division. 224.91 J / 10 m = 224.91 kg*m^2/s^2 / 10 m = 22.491 kg*m/s^2 = 22.491 N Rounding to 3 significant figures gives an average force of 22.5 newtons.</span>
3 0
3 years ago
What is the shortest-wavelength x-ray radiation in m that can be generated in an x-ray tube with an applied voltage of 93.3 kV?
VikaD [51]

(a) 1.33\cdot 10^{-11} m

The x-rays in the tube are emitted as a result of the collisions of electrons (accelerated through the potential difference applied) on the metal target. Therefore, all the energy of the accelerated electron is converted into energy of the emitted photon:

e \Delta V = \frac{hc}{\lambda}

where the term on the left is the electric potential energy given by the electron, and the term on the right is the energy of the emitted photon, and where:

e=1.6\cdot 10^{-19}C is the electron's charge

\Delta V = 93.3 kV = 93300 V is the potential difference

h=6.63\cdot 10^{-34} Js is the Planck constant

c=3.00\cdot 10^8 m/s is the speed of light

\lambda is the wavelength of the emitted photon

Solving the formula for \lambda, we find:

\lambda=\frac{hc}{e\Delta V}=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{(1.6\cdot 10^{-19})(93300)}=1.33\cdot 10^{-11} m

(b) 93300 eV (93.3 keV)

The energy of the emitted photon is given by:

E=\frac{hc}{\lambda}

where

h is Planck constant

c is the speed of light

\lambda=1.33\cdot 10^{-11} m is the wavelength of the photon, calculated previously

Substituting,

E=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{1.33\cdot 10^{-11}}=1.50\cdot 10^{-14} J

Now if we want to convert into electronvolts, we have to divide by the charge of the electron:

E=\frac{1.50\cdot 10^{-14} J}{1.6\cdot 10^{-19} J/eV}=93300 eV

(c) The following statements are correct:

The maximum photon energy is just the applied voltage times the electron charge. (1)

The value of the voltage in volts equals the value of the maximum photon energy in electron volts.

In fact, we see that statement (1) corresponds to the equation that we wrote in part (a):

e \Delta V = \frac{hc}{\lambda}

While statement (2) is also true, since in part (b) we found that the photon energy is 93.3 keV, while the voltage was 93.3 kV.

3 0
3 years ago
You and your bicycle have combined mass 80.0 kg. When you reach the base of a bridge, you are travelling along the road at 7.50
Sonja [21]

We have that K.E and work done is

  • K.E=-1890J
  • W=2186J

From the Question we are told that

mass= 80.0 kg

Velocity= 7.50 m/s.

vertical distance of 5.20 m

Slowed to 3.00 m/s.

Generally the equation for Kinetic energy   is mathematically given as

K.E=\frac{mv^2}{2}-\frac{mv^2}{2}\\\\K.E=\frac{80*3^2}{2}-\frac{80*7.5^2}{2}

K.E=-1890J

B)

P.E=mgh\\\\P.E=80*9.8*5.2\\\\P.E=4076

Therefore

W=4076-1890J

W=2186J

For more information on this visit

brainly.com/question/12669551?referrer=searchResults

4 0
3 years ago
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