Kinematics is the branch of Physics that deals with
the mathematical methods of describing motion.
Answer:
Q = 230.36 C
Explanation:
Given
R = 3.54 Ω
t = 30'45" = (30')*(60"/1') + 45" = 1845 s
V = 442 mV = 442*10⁻³V
Q = ?
We can use Ohm's Law in order to get I as follows
V = I*R ⇒ I = V / R
⇒ I = 442*10⁻³V / 3.54 Ω = 0.1248 A
Finally we use the formula
I = Q / t ⇒ Q = I*t = (0.1248 A)(1845 s)
⇒ Q = 230.36 C
I think it is 4 cm because if you look hard enough and work the problem the number pops in you head. Lol
Answer:
= 3289.8 m / s
Explanation:
This exercise can be solved using the definition of momentum
I = ∫ F dt
Let's replace and calculate
I = ∫ (at - bt²) dt
We integrate
I = a t² / 2 - b t³ / 3
We evaluate between the lower limits I=0 for t = 0 s and higher I=I for t = 2.74 ms
I = a (2,74² / 2- 0) - b (2,74³ / 3 -0)
I = a 3,754 - b 6,857
We substitute the values of a and b
I = 1500 3,754 - 20 6,857
I = 5,631 - 137.14
I = 5493.9 N s
Now let's use the relationship between momentum and momentum
I = Δp = m - m v₀o
I = m - 0
= I / m
= 5493.9 /1.67
= 3289.8 m / s