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Marina86 [1]
3 years ago
6

If 3 workers can paint a room in 2 hours, then approximately how long does it take 4 workers to paint the same room? Assume the

time needed to paint the room is inversely proportional to the number of workers.
Mathematics
2 answers:
Olin [163]3 years ago
6 0

It takes 1.5 hours for 4 workers to paint the same room

<em><u>Solution:</u></em>

Given that 3 workers can paint a room in 2 hours

To find: Time taken for 4 workers to paint the same room

Assume the time needed to paint the room is inversely proportional to the number of worker

time $ \propto \frac{1}{\text { number of workers }}\\\\time =k \times \frac{1}{\text { number of workers }}

Where, "k" is the constant of proportionality

<em><u>3 workers can paint a room in 2 hours</u></em>

Substitute number of workers = 3 and time = 2 hours

time =k \times \frac{1}{\text { number of workers }}\\\\2 = k \times \frac{1}{3}\\\\k = 6

Therefore,

\text {time}=6 \times \frac{1}{\text { number of workers }}

To find time taken for 4 workers to paint the same room, substitute number of workers = 4 in above expression

time = 6 \times \frac{1}{4} = 1.5

Thus it takes 1.5 hours for 4 workers to paint the same room

Elina [12.6K]3 years ago
6 0

Answer:

1.5 hours.............

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3 years ago
(-6,1) is a point on the graph of y=g(x)
NNADVOKAT [17]

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(-7, -4)

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(-4, 1)

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So the point in the graph of y = g (x + 1) -5 is

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The transformation

y = -2g(x -2) +4

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The transformation

y=g(2x+2)

Multiply the input variable (x) by 2 and then add two units

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3 years ago
Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3
aliina [53]

Answer:

C) more than the absolute value of the critical value, we can conclude that the average monthly rate for an assisted-living facility is not equal to $3,300.

Step-by-step explanation:

Hello!

Interest hypothesizes is " the average monthly rate for one-bedroom assisted-living facility is equal to $3300" symbolically: μ = 3300

The study variable is:

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Since there is no information about the distribution of the variable, to be able to study the population mean, I'll assume that the variable has a normal distribution.

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The statistic to use, considering that there is no known population information and the sample size, is a Student t:

t= <u> X[bar] - μ </u> ~t_{n-1}

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Using the sample data, calculate the statistic value:

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The rejection region for this test is two-tailed, with critical values:

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I hope it helps!

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