The point with the greatest distance to the origin is given by:
B. (-3, 3).
<h3>What is the distance between two points?</h3>
Suppose that we have two points, 
and 
. The distance between them is given by:
The origin is given by point (0,0), hence the distance of a point (x,y) to the origin is given by:
D = sqrt(x² + y²).
Hence the distances for each point given in the problem are:
- A. Distance = sqrt((-4)² + (-1)²) = sqrt(17).
- B. Distance = sqrt((-3)² + (3)²) = sqrt(18).
- C. Distance = sqrt((4)² + 0²) = sqrt(16).
- D. Distance = sqrt((2)² + 3²) = sqrt(13).
Hence option B has the greatest distance.
More can be learned about the distance between two points at brainly.com/question/18345417
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Let p be
the population proportion. <span>
We have p=0.60, n=200 and we are asked to find
P(^p<0.58). </span>
The thumb of the rule is since n*p = 200*0.60
and n*(1-p)= 200*(1-0.60) = 80 are both at least greater than 5, then n is
considered to be large and hence the sampling distribution of sample
proportion-^p will follow the z standard normal distribution. Hence this
sampling distribution will have the mean of all sample proportions- U^p = p =
0.60 and the standard deviation of all sample proportions- δ^p = √[p*(1-p)/n] =
√[0.60*(1-0.60)/200] = √0.0012.
So, the probability that the sample proportion
is less than 0.58
= P(^p<0.58)
= P{[(^p-U^p)/√[p*(1-p)/n]<[(0.58-0.60)/√0...
= P(z<-0.58)
= P(z<0) - P(-0.58<z<0)
= 0.5 - 0.2190
= 0.281
<span>So, there is 0.281 or 28.1% probability that the
sample proportion is less than 0.58. </span>
a f(a) is the function f(x) where x is replaced by a.
So we have
(3x^2 + x + 3 - (3a^2 + a + 3)) / ( x - a)
= (3x^2 - 3a^2 + x - a) / (x = a) Answer
b (3(x + h)^2 + x + h + 3 - (3x^2 + x + 3)) / h
= (3x^2 + 6xh + 3h^2 + x + h - 3x^2 - x - 3) ) / h
= (6xh + h + 3 h^2) / h
= 6x + 3h + 1 Answer
Margin of error, e = Z*SD/Sqrt (N), where N = Sample population
Assuming a 95% confidence interval and substituting all the values;
At 95% confidence, Z = 1.96
Therefore,
0.23 = 1.96*1.9/Sqrt (N)
Sqrt (N) = 1.96*1.9/0.23
N = (1.96*1.9/0.23)^2 = 262.16 ≈ 263
Minimum sample size required is 263 students.
