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Agata [3.3K]
3 years ago
6

How do u work this out and what's the answer

Mathematics
1 answer:
I am Lyosha [343]3 years ago
6 0
1) you would need to turn both fractions so they have a common denominator, that would be 2 2/4 and 3/4
2) then subtract : 2 2/4 - 3/4, and you would subtract numerators and the whole number, but you keep the denominator the same. However, you cannot subtract 2 and 3 in this case, so you need to change 2 2/4 to 1 5/4 (they are still equivalent)
3) 1 5/4 - 3/4 = 1 2/4, which simplified version is 1 1/2
Therefore, the answer is 1 and 1/2
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HELP AGAIN PLEASE I TRIED IT ON MY OWN AND FAILED :(
Alex787 [66]

Answer:  ∠ J = 62° , ∠ K = 59° , ∠ L = 59°

<u>Step-by-step explanation:</u>

It is given that it is an Isosceles Triangle, where L J ≅ K J

It follows that ∠ K ≅ ∠ L

         ⇒ 5x + 24 = 4x + 31

         ⇒   x + 24 =         31

         ⇒   x         =           7

Input the x-value into either equation to solve for  ∠ K &  ∠ L:

∠ K = 5x + 24

      = 5(7) + 24

      = 35 + 24

       = 59

∠ K ≅ ∠ L  ⇒   ∠ L = 59

Next, find the value of  ∠ J:

∠ J +  ∠ K +  ∠ L = 180    Triangle Sum Theorem

∠ J  +   59  +  59 = 180

∠ J          + 118     = 180

∠ J                       = 62

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3 years ago
I just need answers to the odd numbered questions.<br> I would appreciate the help<br><br> 35 points
Misha Larkins [42]

Answer:

Step-by-step explanation:

Combine real terms and combine complex terms

1) 3 + 2i + 2 - 5i = 3 +2 + 2i - 5i

                          = 5 + (2-5)i

                          = 5 + (-3)i

                          = 5 - 3i

3) 2 - (1 - 2i) + (4 -5i ) - (1 - 3i)  = 2 -1 + 2i + 4 - 5i - 1 + 3i

           {- is distributed to (1 - 2i) & - is distributed to (1- 3i)}

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5) 4 - 3i + 4 + 3i = 4 +4 -3i + 3i

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7) (3 - 2i)² + (3 +2i) = 3² - 2*3*2i + (2i)² + 3 + 2i     {(a - b)² = a² - 2ab +b²}

= 9 -12i + 4i² + 3 + 2i

= 9 - 12i + 4*(-1) + 3 + 2i       {i²  = -1}

= 9 +3 - 4 - 12i +2i

= 8 - 10i

9) (a +b)^{4} - (a - b)^{4} = 8ab(a^{2} +b^{2})\\\\\\Here, \ a = 1 \ and \ b = i\\\\\\(1+\sqrt{-1})^{4}-(1-\sqrt{-1})^{4}=(1+\sqrt{i^{2}})^{4}-(1-\sqrt{i^{2}})^{4}\\\\=(1+i)^{4}-(1-i)^{4}\\\\=8*1*i(1^{2}+i^{2})\\\\=8i*(1 -1)\\\\=8i*0\\\\=0

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