Rachel mows 5 lawns in 8 hours this rate how many lawns can she mow in 40 hours

Find the distance between the points (−5,2) and (9.2)

forsale [732]

Step-by-step explanation:

Formula Used

By distance formula,

d (A,B)=√[(x₁ - x₂)² + (y₁ - y₂)²]

$\sf \longmapsto \: D = √(x2-x1)²+(y2-y1)²$

$\sf \longmapsto= √(9+5)²+(2-2)²$

$\sf \longmapsto= = √14²+09$

$\sf \red \longmapsto \boxed{= 14}$

4 0

2 years ago

Simplify 7x²-x² how to simplify this maths question

kondaur [170]

Hi student, let me help you out! :)

. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .

We are asked to simplify the expression $\large\pmb{7x^2-x^2}$ .

$\triangle~\fbox{\bf{KEY:}}$

Combine like terms! :)

That's exactly what we need to do - combine like terms.

So, we subtract:

$\star~\large\pmb{7x^2-x^2}$

Which gives us:

$\star~\large\pmb{6x^2}$

Hope it helps you out! :D

Ask in comments if any queries arise.

#StudyWithBrainly

~Just a smiley person helping fellow students :)

6 0

1 year ago

The Venn diagram shows the results of two events resulting from rolling a number cube.

tankabanditka [31]

Answer:

$P(A|B)=\frac{2}{3}$

$P(A)*P(B)=\frac{1}{3}$

$P(A) =\frac{2}{3}$

$P(B) =\frac{1}{2}$ .

Step-by-step explanation:

We use the Venn diagram to calculate the desired probabilities.

Note that there are 6 possible results in the sample space

S = {1, 2, 3, 4, 5, 6}

Then note that in the region representing the intercept of A and B there are two possible values.

So

$P (A\ and\ B) = \frac{2}{6} = \frac{1}{3}$

In the region that represents event A there are 4 possible outcomes {4, 5, 1, 2}

So

$P(A) = \frac{4}{6} = \frac{2}{3}$

In the region that represents event B there are 3 possible outcomes {1, 2, 6}

So

$P(B) = \frac{3}{6} = \frac{1}{2}$ .

Now

$P(A | B)=\frac{P(A \ and\ B)}{P(B)}\\\\P(A | B)=\frac{\frac{1}{3}}{\frac{1}{2}}\\\\P(A|B)=\frac{2}{3}$

$P(A)*P(B)=\frac{2}{3}*\frac{1}{2}=\frac{1}{3}$

6 0

3 years ago

(10.02)

melisa1 [442]

Answer:

$sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}$

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

$Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}$

Therefore:

$sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}$

$cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}$

$Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}$

4 0

3 years ago

Solve 29 – 3:= 5x + 5 for x.

mojhsa [17]

Answer:

x=4.2

Step-by-step explanation:

29-3=5x+5

21=5x, x=21/5=4.2

3 0

2 years ago

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