Answer:
p = - 5, p = - 1
Step-by-step explanation:
Given
-
= 
Multiply through by the LCM of (p - 5)(p + 3)
3p(p + 3) - 2(p - 5) = p(p - 5) ← distribute parenthesis
3p² + 9p - 2p + 10 = p² - 5p
3p² + 7p + 10 = p² - 5p ( subtract p² - 5p from both sides )
2p² + 12p + 10 = 0 ← divide through by 2
p² + 6p + 5 = 0 ← in standard form
(p + 1)(p + 5) = 0 ← in factored form
Equate each factor to zero and solve for p
p + 1 = 0 ⇒ p = - 1
p + 5 = 0 ⇒ p = - 5

·

=

. This can be simplified to 5x

, because √50 simplifies to 5√2 (since 5x5x2 equals 50) and the square root sign takes x² from x³ and turns it into just x.
Since the p-value of the test is of 0.00001 < 0.01, these results have statistical significance.
<h3>What is the relation between the p-value and the conclusion of the test hypothesis?</h3>
Depends on if the p-value is less or more than the significance level:
- If it is more, the null hypothesis is not rejected, which means that the results do not have statistical significance.
- If it is less, it is rejected, which means that the results have statistical significance.
In this problem, the probability is the p-value, hence since the p-value of the test is of 0.00001 < 0.01, these results have statistical significance.
More can be learned about p-values at brainly.com/question/13873630
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Answer:
Step-by-step explanation:
Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).
- Brown:

- Yellow or Blue:
....add the numerators
- Not Green:
.... since the sum of all the rest is 80%
- Stiped:
.... there are 0 striped candies.
Assuming the <u><em>ratios/percentages</em></u> of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.
- 3 Browns:

- the 1st and 3rd are red while the middle is any. We multiply 15% * (total of all minus red which is 85%) * 15% like so.

- None are Yellow: multiply the percent of all minus yellow three times.

- At least 1 green: multiply the percent of green by 100% twice, since the other two can by any
