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lyudmila [28]
3 years ago
14

a pet boarder keeps a dog to cat ratio of 5:2 is it a border has a room 98 animals and how many of them can be dogs

Mathematics
1 answer:
My name is Ann [436]3 years ago
8 0

I'm not sure how the correct way to do this would be but if you have a ratio that is 5:2 think of it as having 5 groups of animals and 2 groups of animals.

Find the number by dividing the total amount of animals 98/7 = 14.

We know that there are 5 groups of cats, the ratio for 5 cats. 14 x 5 = 70.

The remainder is dogs, which has a ratio of 2:5. 14 x 2 = 28.

70 + 28 = 98.

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URGENT! PLEASE HELP.
uysha [10]

Answer: a) BC = 1386.8 ft

b) CD = 565.8 ft

Step-by-step explanation:

Looking at the triangle,

AD = BD + 7600

BD = AD - 7600

Considering triangle BCD, we would apply the the tangent trigonometric ratio.

Tan θ = opposite side/adjacent side. Therefore,

Tan 24 = CD/BD = CD/(AD - 700)

0.445 = CD/(AD - 700)

CD = 0.445(AD - 700)

CD = 0.445AD - 311.5 - - - - - - - -1

Considering triangle ADC,

Tan 16 = CD/AD

CD = ADtan16 = 0.287AD

Substituting CD = 0.287AD into equation 1, it becomes

CD = 0.445AD - 311.5

0.287AD = 0.445AD - 311.5

0.445AD - 0.287AD = 311.5

0.158AD = 311.5

AD = 311.5/0.158

AD = 1971.52

CD = 0.287AD = 0.287 × 1971.52

CD = 565.8 ft

To determine BC, we would apply the Sine trigonometric ratio which is expressed as

Sin θ = opposite side/hypotenuse

Sin 24 = CD/BC

BC = CD/Sin24 = 565.8/0.408

BC = 1386.8 ft

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