Neutral mutation is a nucleotide change in the DNA of the leading to the replacement of one amino acid by another amino acid possessing the same physicochemical properties.

example: AAA to AGA (Lysine to Arginine).

both these two amino acids are positively charged, so the charge of the protein will not change

7 0

3 years ago

Complete the passage to describe sexual reproduction.

hoa [83]

Answer:

reproductive cells, or sex cells are called GAMETES

female reproductive cells are called EGGS

male reproductive cells are called SPERM

Explanation:

8 0

3 years ago

Read 2 more answers

This table incudes the characteristics of all major kingdoms.

FrozenT [24]

B Eubacteria. hope this helps :3

3 0

3 years ago

. In this example, red flower coloring is dominant to white, and your population of 200 plants has 150 plants with red flowers.

AnnyKZ [126]

Answer:

a) The allele frequencies are - $p= 0.8660\\q= 0.134$

b) Genotype frequencies for this population- $p^2=0.75, q^2= 0.0179, 2pq = 0.2321$

Explanation:

Given ,

Red color of flower is dominant to white color flower

Let "R" represents allele for red color and "r" represents allele for white color

out of $200$ flower, $150$ are red flowers.

So the frequency of red flowers with genotype "RR" is equal to

$p^{2} = \frac{150}{200} \\p^{2} =0.75$

As per hardy Weinberg's I equilibrium equation -

$p+q=1\\p=\sqrt{p^2} \\p=\sqrt{0.75} \\p= 0.8660\\q= 1-p\\q= 1-0.8660\\q = 0.134$

a) The allele frequencies are - $p= 0.8660\\q= 0.134$

Frequency of genotype "rr" i.e homozygous recessive white flower is

$q^{2} \\0.134^2\\q^2 = 0.0179\\$

Substituting the values of $p^2$ and $q^2$ , in below equation, we get -

$p^2+2pq+q^2=1\\2pq= 1-p^2-q^2\\2pq= 1-0.75-0.0179\\2pq=0.2321$

b) Genotype frequencies for this population- $p^2=0.75, q^2= 0.0179, 2pq = 0.2321$

8 0

3 years ago