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4 years ago

Find the force of a 600 kg car experiences accelerating from 10 km/hr to 35 km/hr in 3 seconds?

1 answer:

3 0

Given,
m=600 kg
u=10 km/hr
v=35 km/hr
t= 3 sec
a=?
F=?

To find a:
u=10 km/hr=5/18*10=25/6=4.16m/s
v=35 km/hr=5/18*35=175/18=9.72m/s
t=3 sec

Now we have,
u=4.16m/s
v=9.72m/s
t=3 sec

To find acceleration:
a=(v-u)/t
a=( 9.72-4.16)/3
a=5.56/3
a=1.85m/s^2

To find F:
m=600 kg
a=1.85 m/s^2

F=ma
F=600*1.85
F=1110N

Therefore, F=1110N

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Answer:

$F=7.96*10^{-11}N$

Explanation:

According to Coulomb's law, the magnitude of the electric force between two equals charges (q) is given by:

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3 years ago

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The answer to what experimental result required considering the particle nature of light is A. The ultraviolet catastrophe of blackbody radiation.

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4 years ago

a 100g ice cube at 0 degrees celsius is placed in 650 grams of water at 25 degrees celsius. When the mixture reaches equillibriu

Artyom0805 [142]

Answer:

The latent heat of fusion of water is 334.88 Joules per gram of water.

Explanation:

Let the latent heat of ice be 'x' J/g

1) Thus heat absorbed by 100 gram of ice to get converted into water equals

$Q_1=100\times x$

2) heat energy required to raise the temperature of water from 0 to 25 degree Celsius equals

$Q_2=100\times 4.186\times 11=4604.6Joules$

Thus total energy needed equals $Q_1+Q_2=100x+4604.6$

3) Heat energy released by the decrease in the temperature of water from 25 to 11 degree Celsius is

$Q_3=650\times 4.186\times (25-11)\\\\Q_{3}=38092.6Joules$

Now by conservation of energy we have

$Q_1+Q_2=Q_3\\\\100x+4604.6=38092.6\\\\\therefore x=\frac{38092.6-4604.6}{100}=334.88J/g$

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3 years ago

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4 years ago

The largest graduated cylinder in my lab holds 2 L and has an inner diamter (the part that holds the water) of 8 cm. When it is

mestny [16]

Answer:

3924 Pa

Explanation:

Volume of cylinder = 2 L = 0.002 m^3 (1000 L = 1 m^3)

diameter of the inner cylinder = 8 cm = 0.08 m (100 cm = 1 m)

radius of the inner cylinder = diameter/2 = 0.08/2 = 0.04 m

area of the inner cylinder = $\pi r^{2}$

where $\pi$ = 3.142,

and r = radius = 0.04 m

area of inner cylinder = 3.142 x $0.04^{2}$ = 0.005 m^2

height h of the water in this cylinder = volume/area

h = 0.002/0.005 = 0.4 m

pressure at the bottom of the cylinder due to the height of water = pgh

where

p = density of water = 1000 kg/m^3

g = acceleration due to gravity = 9.81 m/s^2

h = height of water within this cylinder = 0.4 m

pressure = 1000 x 9.81 x 0.4 = 3924 Pa

3 0

3 years ago

Find the force of a 600 kg car experiences accelerating from 10 km/hr to 35 km/hr in 3 seconds?​

Find the force of a 600 kg car experiences accelerating from 10 km/hr to 35 km/hr in 3 seconds?