calculate the electrical potential at a point P a distance of 1 m from either two to charge of +10 micro coulomb and -5 micro co
ulomb which are 10 cm apart calculate also the potential energy of a +2 micro coulomb charge placed at a point p
1 answer:
Answer:
a) V = 45 10³ V, b) U = 4.59 J
Explanation:
a) The electric potential for a series of point charges is
V = k ∑
in this case point P is at a distance of 1 m from each charge, so the point is located perpendicular to the charges at its midpoint
V = k ( )
V = 9 10⁹ (10 - 5/ 1) 10⁻⁶
V = 45 10³ V
b) the potential energy is
U = k ( )
where r = 1m and r₂ is the distance between the two charges r₂ = 0.10 m
U = 9 10⁹ (10 2 / 1 - 5 2/1 - 10 5 /0.10) 10⁻¹²
U = 9 10⁻³ 510
U = 4.59 J
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Answer:b
Explanation:
Because I don’t know
I think it’s current= A / C
Answer:
= 8.46 × 10³N
Explanation:
W = 1.3 × 10⁴
v₁ = 0
v (friction) = 95km/h = 26.4 m/s
t = 5s
f = 1450N
mass of body = W / g
=1.3 × 10⁴ / 9.8
=1327 kg
v(friction) = v + at
substitute in eqn 1
26.4 = 5a
a = 5.28 m/s
Force Net = F₁ + F₂ + F₃ = ma
F (engine) = ma + F
= 1327 (5.28) + 1450
= 8.46 × 10³N
Answer:
1350kgm/s
Explanation:
Given parameters:
Mass of footballer = 75kg
Velocity = 18m/s
Unknown:
Momentum = ?
Solution:
The momentum of a body is the quantity of motion it posses.
It is mathematically given as:
Momentum = mass x velocity
Momentum = 75 x 18
Momentum = 1350kgm/s
J.J. Thomson's experiments provided evidence that an atom B.contains negatively charged particles.
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