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KIM [24]
4 years ago
6

Pls hurry I need it

Mathematics
2 answers:
Juli2301 [7.4K]4 years ago
8 0
C. Using the commutative property
marissa [1.9K]4 years ago
8 0
Answer is given below look carefully

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If you know the answer to this let me know pls!
Bad White [126]

Answer:

I think it is C.

Step-by-step explanation:

Have a good day. :-)

5 0
3 years ago
A hackberry tree has roots that reach a depth of
Degger [83]

Answer:

24.6967 meters

Step-by-step explanation:

The roots of the tree go 6 and 5 over 12 meters below the ground level.

Now, 6 and 5 over 12 meters is equivalent to 6.4167 meters.

Again the top of the tree is 18.28 meters high from the ground level.

Therefore, the total height of the tree from the bottom of the root to the top is  

(6.4167 +18.28) = 24.6967 meters (Answer)

5 0
3 years ago
Work out 3√−64<br> the 3 is small ( cubed )
Alekssandra [29.7K]

3√-64 = -4

The answer is -4.

7 0
3 years ago
Scientists modeled the intensity of the sun, I, as a function of the number of hours since 6:00 a.m., h, using the
MAVERICK [17]

The functions are illustrations of composite functions.

<em>The soil temperature at 2:00pm is 67</em>

The given parameters are:

\mathbf{I(h) =\frac{12h - h^2}{36}} ---- the function for sun intensity

\mathbf{T(I) =\sqrt{5000I}} -- the function for temperature

At 2:00pm, the value of h (number of hours) is:

\mathbf{h = 2:00pm - 6:00am}

\mathbf{h = 8}

Substitute 8 for h in \mathbf{I(h) =\frac{12h - h^2}{36}}, to calculate the sun intensity

\mathbf{I(8) =\frac{12 \times 8 - 8^2}{36}}

\mathbf{I(8) =\frac{32}{36}}

\mathbf{I(8) =\frac{8}{9}}

Substitute 8/9 for I in \mathbf{T(I) =\sqrt{5000I}}, to calculate the temperature of the soil

\mathbf{T(8/9) =\sqrt{5000 \times 8/9}}

\mathbf{T(8/9) =\sqrt{4444.44}}

\mathbf{T(8/9) =66.67}

Approximate

\mathbf{T(8/9) =67}

Hence, the soil temperature at 2:00pm is 67

Read more about composite functions at:

brainly.com/question/20379727

5 0
2 years ago
Please help me with 19 and 20 please
lesya [120]

9514 1404 393

Answer:

  19. B -- continued, but modest ...

Step-by-step explanation:

19. There is no decline or decrease indicated on this graph. If growth were exponential, the graph would be concave upward, which it is not. There is continued growth indicated.

__

20. The percentage change from 2005 to 2010 is ...

  (60 -20)/20 × 100% = 2 × 100% = 200%

One might compute an average rate of change per year of ...

  200%/(5 yr) = 40%/yr

_____

<em>Additional comment</em>

As with any statement of percentage, you need to be very clear about what the base is.

Here, 100% is the number of farms in 2005, so an increase of 40% per year is an increase by 40% of the number in 2005. That is very different from 40% of the number in the previous year, which is how an annual percentage increase is usually interpreted. (The average annual rate of change is closer to 24% with respect to the previous year's number.)

3 0
3 years ago
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