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likoan [24]
3 years ago
6

A bug splatters on the windshield of a moving car. Describe the 1. Forces 2. Impulses 3. Momentum changes 4. And accelerations o

f both the bug and the car
Mathematics
1 answer:
uranmaximum [27]3 years ago
4 0

Answer:

acceleration=force/mass

Due to variation in the mass[ as same force as per magnitude acts on both of them] the acceleration developed in the bug will be more and the acceleration developed in the car is negligible.

impulse=change in momentum

The impulse of bug is more and that of car is small.

momentum changes=change in momentum

force=change in momentum/time of contact

the force exerted by car on the bug will be more than the converse

Total. momentum is conserved , so magnitude of change in momemtum or impulse is same. By Newtons third law, since the bug have smaller mass, its change in magnitude of velocity is larger.

Step-by-step explanation:

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Answer:

The correct option is;

∠A ≅ ∠X

Step-by-step explanation:

The given coordinates of the points of triangle ACB are;

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The given coordinates of the points of triangle XYZ are;

X(0, 8), Y(8, 8), Z(6, 2), therefore, we have

The length. l. of segment is given by the following formula;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

For the length of the segment AC; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-1, 3), l = √(10)

For the length of the segment AB; (x₁, y₁) = (-4, 4), (x₂, y₂) = (-4, 0), l = 4

For the length of the segment BC; (x₁, y₁) = (-4, 0), (x₂, y₂) = (-1, 3), l = 3·√2

For the length of the segment XY; (x₁, y₁) = (0, 8), (x₂, y₂) = (8, 8), l = 8

For the length of the segment XZ; (x₁, y₁) = (0, 8), (x₂, y₂) = (6, 2), l = 6·√2

For the length of the segment ZY; (x₁, y₁) = (6, 2), (x₂, y₂) = (8, 8), l = 2·√(10

Therefore;

XY ~ AB, XZ ~ BC, ZY ~ AC

Which gives;

∠A ≅ ∠X, ∠B ≅ ∠Y, ∠C ≅ ∠Z

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3 years ago
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Answer:

A) 8 treatments

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and they are :

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