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3 years ago

2 Simplify. Rewrite the expression in the form 8». (8-8)(83) Please help

Mathematics

1 answer:

marishachu [46]3 years ago

5 0

Answer:

$8^{-5}$

Step-by-step explanation:

When you multiply exponents together, you simply add them.

-8 + 3 = -5.

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How do u simplify 5x^2-8x-12 subracted from -4x^2+2x-8

Nady [450]

Answer:

- 9x² + 10x + 4

Step-by-step explanation:

Calculate the subtraction as

- 4x² + 2x - 8 - (5x² - 8x - 12 ) ← distribute parenthesis by - 1

= - 4x² + 2x - 8 - 5x² + 8x + 12 ← collect like terms

= - 9x² + 10x + 4

7 0

3 years ago

This is due like right now, please help me!!!!

Varvara68 [4.7K]

$\bold{\huge{\orange{\underline{ Solution }}}}$

$\bold{\underline{ Given \: Rules}}$

The sum of the number in each of the four rows is the same
The sum of the numbers in each of the three columns is the same
The sum of any row does not equal the sum of any column

$\bold{\underline{ Let's \: Begin}}$

According to the Second rule :-

$\sf{ 75+b+83=76+80+d=a+81+85+78+c+e }$

$\sf{ 158 + b = 156 + d = 166 + a = 78 + c + e ...(1)}$

According to the first rule :- 

$\sf{ 75+76+a+78 = b+80+81+c = 83+86+d+e}$

$\sf{ 229 + a = 161 + b + c = 168 + d + e ...(2)}$

From ( 1 ) we got :-

$\sf{ 158 + b = 166 + a, 156 + d = 166 + a }$

$\sf{ b = 166 - 158 + a, d = 166 - 156 + a }$

$\sf{ b = 8 + a, d = 10 + a ...(3)}$

Subsitute (3) in ( 2 ) :-

$\sf{229+a = 161+8+a+c = 168+10+a+e}$

$\sf{ 229+a = 169+a+c = 178+a+e}$

We can write it as :-

$\sf{ 229+a = 169+a+c \:or\:229+a = 178+a+e}$

$\sf{ c = 299-169+a-a\:or\:e = 229-178+a-a}$

$\sf{ c = 60 \: and \: e = 51 }$

Subsitute the value of c and e in ( 1 ):-

$\sf{ 158 + b = 156 + d = 166 + a = 78 + 60 + 51 }$

$\sf{ 158 + b = 156 + d = 166 + a = 189}$

Now, 

$\sf{ For \: b, 158 + b = 189 }$

$\sf{ b = 189 - 158 }$

$\sf{ b = 31}$

$\sf{ For \: d , 156 + b = 189 }$

$\sf{ d = 189 - 156 }$

$\sf{ d = 33}$

$\sf{ For \: a, 166 + a = 189 }$

$\sf{ a = 189 - 166 }$

$\sf{ a = 23 }$

Hence, The value of a, b, c, d and e is 23, 31 ,60 ,33 and 51 .

8 0

3 years ago

What is the equation of a line in general form that passes through the point (1,-2) and has a slope of 1/3

ser-zykov [4K]

Answer:

(y+2) = (1/3)(x-1)

Answer in point-slope form, you can rearrange this into the form which you need.

Step-by-step explanation:

recall that the general point-slope form of a linear equation looks like :

(y - y₁) = m(x - x₁)

where m is the slope and (x₁,y₁) is any point on the line

here we are given m = 1/3 and (x₁,y₁)=(1,-2)

simply substitute this info into the general equation above

(y - y₁) = m(x - x₁)

(y - (-2) ) = (1/3)(x - 1)

(y+2) = (1/3)(x-1) Answer in point-slope form, you can rearrange this into the form which you need.

4 0

3 years ago

The area of a rectangle is 14 m2 , and the length of the rectangle is 3 m less than double the width. find the dimensions of the

muminat

Width =3.5, length = 4

Let's make a few equations to summarize what we know.:
a = 14
l = 2w -3
a = wl

Now let's substitute the expression for l into the expression for area and solve.
a = w(2w - 3)
a = 2w^2 - 3w
14 = 2w^2 - 3w

0 = 2w^2 - 3w - 14

which factors into
(2w - 7) (w + 2)

Solving for w
2w - 7 = 0
2w = 7
w = 3.5

w+2 = 0
w = -2

So w can be either 3.5 or -2. Since a negative width doesn't make sense, w = 3.5

Let's verify
w = 3.5
l = 2w - 3
l = 2*3.5 - 3
l = 7 - 3
l = 4
a = wl
a = 3.5 * 4
a = 14

So the width is 3.5 and the length is 4.

3 0

3 years ago

How do you write 2.305 as a fraction in simplest form

choli [55]

You put 2.305 over 10000 so 2305/1000 /5 each side so 2 61/200 would be simplest form hope that helped

5 0

3 years ago